Answer:


Step-by-step explanation:
Given


Required
Determine the volume of the solid generated
Using the disk method approach, we have:

Where


So:

Where
So:
Apply the following half angle trigonometry identity;
![\cos^2(x) = \frac{1}{2}[1 + \cos(2x)]](https://tex.z-dn.net/?f=%5Ccos%5E2%28x%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5B1%20%2B%20%5Ccos%282x%29%5D)
So, we have:
![\cos^2(2x) = \frac{1}{2}[1 + \cos(2*2x)]](https://tex.z-dn.net/?f=%5Ccos%5E2%282x%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5B1%20%2B%20%5Ccos%282%2A2x%29%5D)
Open bracket

So, we have:
![V = \pi \int\limits^{\frac{\pi}{4}}_0 {[\frac{1}{2} + \frac{1}{2}\cos(4x)]} \, dx](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%5Cint%5Climits%5E%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%7D_0%20%7B%5B%5Cfrac%7B1%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B2%7D%5Ccos%284x%29%5D%7D%20%5C%2C%20dx)
Integrate
![V = \pi [\frac{x}{2} + \frac{1}{8}\sin(4x)]\limits^{\frac{\pi}{4}}_0](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%5B%5Cfrac%7Bx%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B8%7D%5Csin%284x%29%5D%5Climits%5E%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%7D_0)
Expand
![V = \pi ([\frac{\frac{\pi}{4}}{2} + \frac{1}{8}\sin(4*\frac{\pi}{4})] - [\frac{0}{2} + \frac{1}{8}\sin(4*0)])](https://tex.z-dn.net/?f=V%20%3D%20%5Cpi%20%28%5B%5Cfrac%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B8%7D%5Csin%284%2A%5Cfrac%7B%5Cpi%7D%7B4%7D%29%5D%20-%20%5B%5Cfrac%7B0%7D%7B2%7D%20%2B%20%5Cfrac%7B1%7D%7B8%7D%5Csin%284%2A0%29%5D%29)
So:
or

Answer:
8
Step-by-step explanation:
6t - 20 - 32u = ?
t = 6 u = 1/4 [.25]
6*(6) - 20 - 32*(1/4)
36 - 20 - 8 = ?
? = 8
i hope this helps!
:)
it would mean a lot if you marked as brainliest :)
Answer:
x = -11, y = 10, z = 4
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Answer:
There is no diagram for our observation. Please refine your question next time.
Step-by-step explanation:
<h3>
Answer: B) 60</h3>
================================================
Explanation:
Whenever the angle theta is between 0 and 90, the reference angle is exactly that value.
It's only when you get to other quadrants is when things get a bit tricky. Right now we're in quadrant 1, often written as Q1.
-------------------
Extra info:
- If theta is between 90 and 180, then the reference angle is 180-theta. This region is Q2
- If theta is in quadrant 3, between 180 and 270, then the reference angle is theta-180. The order of subtraction is important since x-y is the not the same as y-x.
- Lastly, if theta is between 270 and 360 (in Q4), then the reference angle is 360-theta.
- As you can see, we have four quadrants starting with Q1 in the upper right corner. Then we move counterclockwise to get Q2,Q3 and Q4.