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2 years ago

Find the Value of x from the following :

Mathematics

1 answer:

Sonja [21]2 years ago

7 0

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

<h3>Question 1 ~</h3>

$log_{x}(64) = 2$

${x}^{2} = 64$

$x = \sqrt{64}$

$x = \sqrt{8 \times 8}$

$x = 8$

<h3>Question 2 ~</h3>

$log_{2}(x) = 5$

$x = 2 {}^{5}$

$x = 32$

I hope it helped ~

You might be interested in

Find a positive angle less than one revolution around the unit circle that is co-terminal with the given angle: 52pi/5

Ludmilka [50]

We know that
Two angles are said to be co-terminal <span>if they have the same initial side and </span>
<span>the same terminal side.
</span>
(52π/5)-----> 10.4π<span>
so
</span>(52π/5)-5*2π------> (2π/5)

the answer is
the positive angle less than one revolution around the unit circle that is co-terminal with angle of 52π/5 is 2π/5

7 0

3 years ago

Read 2 more answers

A statistician calculates that 8% of Americans own a Rolls Royce. If the statistician is right, what is the probability that the

hichkok12 [17]

Answer:

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

A statistician calculates that 8% of Americans own a Rolls Royce.

This means that $p = 0.08$

Sample of 595:

This means that $n = 595$

Mean and standard deviation:

$\mu = p = 0.08$

$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.08*0.92}{595}} = 0.0111$

What is the probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%?

Proportion above 8% + 3% = 11% or below 8% - 3% = 5%. Since the normal distribution is symmetric, these probabilities are equal, and so we find one of them and multiply by 2.

Probability the proportion is less than 5%:

P-value of Z when X = 0.05. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.05 - 0.08}{0.0111}$

$Z = -2.7$

$Z = -2.7$ has a p-value of 0.0035

2*0.0035 = 0.0070

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

8 0

3 years ago

Sixth grade

garri49 [273]

Answer:

11-C

Step-by-step explanation:

Cause 11-C

equels the same amount as the one on the top of 11-C

6 0

2 years ago

This is due today pls help

umka2103 [35]

Answer: the answer is linear

Step-by-step explanation: (not sure what functions it’s talkin about but it is linear)

6 0

2 years ago

3 equivalent ratios for 5/7

riadik2000 [5.3K]

Answer:

10/14, 15/21, and 20,28

Step-by-step explanation:

You just need to multiply a number on the numerator and the denominator. Remember, whatever you do to the numerator you have to do on your denominator.

8 0

3 years ago