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Fittoniya [83]
2 years ago
6

Please answer I need help it is a choose question but I provided pictures of every arrow. FREE 25 points if correct.

Mathematics
1 answer:
Alenkinab [10]2 years ago
8 0
1. positive
2. the last one
3. neg
4. pos
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The difference of d minus 3 divided by 2?​
Allisa [31]

\text{Hey there!}

\text{What is the difference of d minus 3 divided by 2?}\\\\\text{Difference means subtract/subtraction}\\\\\text{Minus would also be subtraction}\\\\\text{Divided by is division}\\\\\text{d would be the start of the problem}\\\\\text{the 3 divided by 2 would be on the right side ( the second part of the equation)}\\\\\boxed{\boxed{\bf{\ Answer:: d-\dfrac{3}2{}}}}}\checkmark

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6 0
2 years ago
X2 – 3x + 10<br><br> What is the answer to this?
Tpy6a [65]

Answer:

-1x+10

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A banner is in the shape of a right triangle. the area is 63 inches. The height of the banner is 4 in less than twice the width
Blizzard [7]
Area=1/2 times base times height
note:bh=base times height

a=1/2bh
b=width

h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0

so
w-9=0
w+7=0

solve each
w-9=0
add 9 to both sdies
w=9

w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded

width=9

subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14


legnth=14 in
width/base=9 in
5 0
3 years ago
What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17
Pepsi [2]

IQR = 6

First locate the median Q_{2} at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles Q_{1} and Q_{3} located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

                     ↑

Q_{2} = 18

Q_{1} = \frac{16+17}{2} = 16.5

Q_{3} = \frac{22+23}{2} = 22.5

IQR = Q_{3} - Q_{1} = 22.5 - 16.5 = 6




4 0
2 years ago
Solve the following equation 2x=12
Luden [163]
Let's solve your equation step-by-step.
2
x
=
12
Step 1: Divide both sides by 2.
2
x
2
=
12
2
x
=
6
Answer:
x
=
6

6 0
1 year ago
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