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german
3 years ago
10

Carlos earns $11.80 per hour working after school. He needs at least $410 to buy a refurbished cell phone. Write and solve an in

equality to find the least amount of hours he must work to be able to buy the phone.
Mathematics
1 answer:
mart [117]3 years ago
6 0
Like 3 hours I think to make it 410
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How do you find a rate of change
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Consider the line y = 2x + 1, shown at the right. Notice that this slope will be the same if the points (1,3) and (2, 5) are used for the calculations. For straight lines, the rate of change<span> (slope) is constant (always the same). For every one unit that is moved on the x-axis, two units are moved on the y-axis.hope this helped. </span>
5 0
3 years ago
A publisher reports that 30% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is
Ierofanga [76]

Answer:

Test statistic = - 2.29

Pvalue = 0.0110

Step-by-step explanation:

The hypothesis :

H0 : p = 0.3

H1 : p < 0.3

Test statistic :

z=pˆ−p/√p(1−p)/n

pˆ = 0.2

Z = (0.20 - 0.30) / √(0.30(1 - 0.30) / 110

Z = - 0.1 / √0.0019090

Z = - 0.1 / 0.0436931

Z = - 2.29

Test statistic = -2.29

The Pvalue :

P(Z < -2.29) = 0.0110

4 0
3 years ago
Y=16 when x=4 , determine y when x=8
Serga [27]
Y= 32 if x= 8, 2 times 16 is 32

4 0
3 years ago
Read 2 more answers
Please help I will reward brainliest
ollegr [7]

Answer:

Straight Angle

Explanation:

Def: An obtuse angle is an angle whose measure is greater than 90 degrees but less than 180 degrees. Def: A straight angle is an angle whose measure is exactly 180 degrees. Def: Two angles are congruent if their measures are exactly the same. Def: Two angles are complementary if their measures add up to 90 degrees.

6 0
3 years ago
Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.
Step2247 [10]

Answer:

Remember, the expansion of (x+y)^n is (x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k, where \binom{n}{k}=\frac{n!}{(n-k)!k!}.

Then,

(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k

Then, the coefficient of the term p^{6-k}q^k is \binom{6}{k}5^{6-k}2^k

a) since 6-k=2, then k=4. So the coefficient of p^2q^4 is

\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000

b) since 6-k=5, then k=1. So, the coefficient of p^5q is

\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500

c) since 6-k=3, then k=3. So, the coefficient of p^3q^3 is

\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000

6 0
3 years ago
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