Answer:
The answer to this question is option 1,2 and 4.
Explanation:
Some html elements does not contain anything or having no content are called empty html elements.for ex:- <br>,<hr> etc.
HTML elements are of two types block and inline.block elements starts with new line for ex:-div,body etc.Inline elements does not starts with new line.for ex:-<style>,<meta>,<head>etc.
Html elements also contains attributes that modify the element for ex:-
<body style="background-color:blue;">
where style is an attribute.
Answer:
When the transmission exceeds 667 packets
Explanation:
In computer networking, a packet is a chunk of data transmitted across the network. The packet size of an Ethernet network is 1.5kilobytes, while the packet size of an IP packet payload is 64 kilobytes.
A switch is a physical network device that connects nodes or workstations while communicating the packets (or frames). The I/O bus size bandwidth is 1Gbps which allows approximately 667 packets. Once this packet size is crossed, the bus becomes a limiting factor or bottle neck.
Answer:
The program in C is as follows:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main(){
int dice [1000];
int count [6]={0};
srand(time(0));
for (int i = 0; i < 1000; i++) {
dice[i] = (rand() %(6)) + 1;
count[dice[i]-1]++;
}
for (int i = 0; i < 6; i++) {
printf("%d %s %d %s",(i+1)," occurs ",count[i]," times");
printf("\n");
}
return 0;
}
Explanation:
This declares an array that hold each outcome
int dice [1000];
This declares an array that holds the count of each outcome
int count [6]={0};
This lets the program generate different random numbers
srand(time(0));
This loop is repeated 1000 times
for (int i = 0; i < 1000; i++) {
This generates an outcome between 1 and 6 (inclusive)
dice[i] = (rand() %(6)) + 1;
This counts the occurrence of each outcome
count[dice[i]-1]++; }
The following prints the occurrence of each outcome
for (int i = 0; i < 6; i++) {
printf("%d %s %d %s",(i+1)," occurs ",count[i]," times");
printf("\n"); }
Answer:
public class Calculator {
public double add(int a, int b){
return a+b;
}
public double substract(int a, int b){
return a-b;
}
public double multiply(int a, int b){
return a*b;
}
public double divide(int a, int b){
if(b>0){
return a/b;
}
else{
System.out.println("Cannot divide by zero");
}
return -1;
}
}
Explanation:
- Using Java Programming Language, the class Calculator is created. There are no fields (Instance variables) and no constructors since these are not required by the question.
- Four methods (functions) are created: add, substract, multiply and divide as specified in the question.
- Note the use of the if statement in the divide() to handle case of illegal division (by 0)
