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quester [9]
3 years ago
5

Which option describes wearable technology?

Computers and Technology
2 answers:
kotykmax [81]3 years ago
7 0
My opinion is the answers A and D. I would choose A if you can only choose one, though.
Ratling [72]3 years ago
4 0

the answer is A , hope that helps :)


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The state licensing bureau recently conducted a survey at Community Hospital. During this review, the surveyors determined that
marshall27 [118]

Answer: Opportunity for Improvement

Explanation:

Any healthcare organization, service, or process that does not reach the established standard or the customer's expectations, is an opportunity for improvement. Furthermore, the Improving Medicare Post-Acute Care Transformation Act (IMPACT) established a quality reporting program aimed to find those opportunities for improvement. Once the problem has been established, is prudent to place an action plan to achieve the desired performance improvement aim.

3 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Declare a character variable letterStart. Write a statement to read a letter from the user into letterStart, followed by stateme
oee [108]
  1. Answer: import java.util.Scanner; public class CharTestt {     public static void main(String[] args) {     System.out.println("Please enter a character ");     Scanner input = new Scanner(System.in);     char letterStart = input.next().charAt(0);     char thenextChar = (char)(letterStart+1);     System.out.print(letterStart);     System.out.println(thenextChar); } } Explanation: Import Scanner Class Prompt user to enter a character Read and save user's input in a variable char letterStart = input.next().charAt(0); Knowing that the next character using ASCII is +1, create a new character variable and add 1 print the character entered and the new character all on same line without spaces
5 0
4 years ago
Using a tag, set the color to green for all tags.
nordsb [41]

Answer:

<style>

p {

background-color: rgb(255, 0, 0);

}

h1 {

background-color: rgb(0, 255, 0);

}

ol {

background-color: rgb(97,51,47);

}

</style>

Explanation:

Put this at the top of your code. It should target the paragraph tag, the header h1 tag, and the Ordered List (OL) tag individually and set their background colors respectively.

It's been a while since I've done CSS so you might have to tweak the syntax a bit, but it should look something like that.

5 0
3 years ago
PLTW IM Chapter 1.2-1.3 i need this please
Luden [163]

<u>Answer:</u>

<em><u>Biomedical Science</u></em>

<em><u>The application of the principles of the natural sciences, especially biology and physiology to clinical medicine</u></em>

<em><u>Control group</u></em>

<em><u>The group in an experiment where the independent variable being tested is not applied so that it may serve as a standard for comparison against the experimental group where the independent variable is applied.</u></em>

<em><u>Dependent Variable</u></em>

<em><u>The measurable affect, outcome, or response in which the research is interested.</u></em>

<em><u>Experiment</u></em>

<em><u>A research study conducted to determine the effect that one variable has upon another variable</u></em>

<em><u>Forensic Science</u></em>

<em><u>The application of scientific knowledge to questions of civil and criminal law</u></em>

<em><u>Hypothesis</u></em>

<em><u>Clear prediction of anticipated results of an experiment</u></em>

<em><u>Independent Variable</u></em>

<em><u>The variable that is varied or manipulated by the researcher</u></em>

<em><u>Negative control</u></em>

<em><u>Control group where the conditions produce a negative outcome. Negative control groups help identify outside influences which may be present that were not accounted for when the procedure was created</u></em>

<em><u>Personal protective equipment</u></em>

<em><u>Specialized clothing or equipment, worn by an employee for protection against infectious materials.(as defined by OSHA)</u></em>

<em><u>Positive control</u></em>

<em><u>Group expected to have a positive result, allowing the researcher to show that the experiment set up was capable of producing results.</u></em>

<em><u>Adenine</u></em>

<em><u>A component of nucleic acids, energy carrying molecule such as ATP, and certain co enzymes. Chemically it is a purine base.</u></em>

<em><u>Chromosome</u></em>

<em><u>Any of the usually linear bodies in the nucleus that contain genetic material.</u></em>

<em><u>Cytosine</u></em>

<em><u>A component of nucleic acids that carries hereditary information in DNA and RNA in cells . Chemically it is a pyrimidine base.</u></em>

<em><u>Deoroxyribonucleic acid</u></em>

<em><u>A double-stranded helical nucleic acid molecule capable of replicating and determining the inherited structure of a cell proteins</u></em>

<em><u>Gel electrophoresis</u></em>

<em><u>The separation of nucleic acids or proteins, on the basis of their size and electrical charge, by measuring their movement through an electrical field in a gel.</u></em>

<em><u>Gene</u></em>

<em><u>A discrete unit of hereditary information consisting of a specific nucleotide sequence in DNA.( or RNA in some viruses).</u></em>

<em><u>Guanine</u></em>

<em><u>A component of nucleic acids that carries hereditary information in DNA and RNA in cells. Chemically it is a purine base.</u></em>

<em><u>Helix</u></em>

<em><u>Something in spiral form.</u></em>

<em><u>Model</u></em>

<em><u>A simplified version of something complex used, for example, to analyze and solve problems or make predictions.</u></em>

<em><u>Nucleotide</u></em>

<em><u>A building block of DNA, consisting of a 5 carbon sugar convalently bonded to a nitrogenous base and a phosphate group.</u></em>

<em><u>Restriction enzymes</u></em>

<em><u>A degradative enzyme that recognizes specific nucleotide sequences and cuts up DNA</u></em>

<em><u>Restriction fragment length polyphorisms (RFLPs)</u></em>

<em><u>Differences in DNA sequences on homologous chromosomes that can result in different patterns of restriction fragment lengths (DNA segments resulting from treatment with restriction enzymes)</u></em>

<em><u>Thymine</u></em>

<em><u>A component of nucleic acid that carries hereditary information in DNA cells. Chemically, it is a pyrimidine base</u></em>

<em><u>Autopsy</u></em>

<em><u>An examination of the body after death usually with such dissections as will expose the vital organs for determining the cause of death</u></em>

<em><u>Bibliography</u></em>

<em><u>a document showing all the sources used to research information</u></em>

<em><u>Citation</u></em>

<em><u>A written reference to a specific work by a particular author or creator which identifies the document in which the work may be found</u></em>

<em><u>Documentation</u></em>

<em><u>The act of creating citations to identify resources used in writing a work</u></em>

<em><u>Health Insurance Portability and Accountability Act (HIPAA)</u></em>

<em><u>A comprehensive set of standards and practices designed to give patients specific rights regarding their personal health information</u></em>

<em><u>Medical examiner</u></em>

<em><u>A physician who performs an autopsy when death may be accidental or violent. He/she may also serve in some jurisdictions as the coroner.</u></em>

Explanation:

This is what I found when I searched up <u>pltw chapter 1.2-1.3 answers.</u>

I did this because there was not really a question in there.

PS:

I'm sorry if this is too long for you to read.

Give me brainliest, if you want to, that is.

7 0
3 years ago
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