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KatRina [158]
2 years ago
12

Be an angel and halp mi pls

Mathematics
2 answers:
larisa [96]2 years ago
8 0

Answer:

Step-by-step explanation:

The mean is just the sum of terms divided by the number of terms.

m=(180+200+210+220+240)/5

m=210

Natalka [10]2 years ago
6 0

Answer:

The mean of the scores at the bowling game is D. 210

Hope this helped! :)

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Write an equation in slope intercept form for the line that passes through (-1, -2) and (3, 4)
LenaWriter [7]

Answer:

The slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given the points

  • (-1, -2)
  • (3, 4)

Determining the slope between (-1, -2) and (3, 4)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-1,\:-2\right),\:\left(x_2,\:y_2\right)=\left(3,\:4\right)

m=\frac{4-\left(-2\right)}{3-\left(-1\right)}

m=\frac{3}{2}

Thus, the slope of the line is:

m = 3/2

substituting m = 3/2 and the point (3, 4) in the slope-intercept form of the line equation

y = mx+b

4=\frac{3}{2}\left(3\right)+b

switch sides

\frac{3}{2}\left(3\right)+b=4

\frac{9}{2}+b=4

subtract 9/2 from both sides

\frac{9}{2}+b-\frac{9}{2}=4-\frac{9}{2}

b=-\frac{1}{2}

now substituting m = 3/2 and b = -1/2 in the slope-intercept form of the line equation

y = mx+b

y=\:\frac{3}{2}x\:+\:\left(-\frac{1}{2}\right)

y=\:\frac{3}{2}x\:-\frac{1}{2}

Therefore, the slope-intercept form of the line equation  is:

  • y=\:\frac{3}{2}x\:-\frac{1}{2}
8 0
2 years ago
Calculate the mean, median, and range of the data in the dot plot.
Mama L [17]

Answer:

median = 5

range = 2

mean = 11

Step-by-step explanation:

7 0
2 years ago
Dan says that all quadrilaterals are parallelograms. Tom says that it is not true. Explain who is correct??
sineoko [7]
Tom is correct, and Dan is wrong. A quadrilateral is a closed figure with four sides, for example, like a kite. A parallelogram is a four sided rectangular figure with opposite sides that are parallel.
6 0
2 years ago
Read 2 more answers
Write an equation of the hyperbola given that the center is at (2, -3), the vertices are at (2, 3) and (2, - 9), and the foci ar
zavuch27 [327]
Check the picture below.

so, the hyperbola looks like so, clearly a = 6 from the traverse axis, and the "c" distance from the center to a focus has to be from -3±c, as aforementioned above, the tell-tale is that part, therefore, we can see that c = 2√(10).

because the hyperbola opens vertically, the fraction with the positive sign will be the one with the "y" in it, like you see it in the picture, so without further adieu,

\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h,  k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}\\
asymptotes\quad  y= k\pm \cfrac{a}{b}(x- h)
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=2\\
k=-3\\
a=6\\
c=2\sqrt{10}
\end{cases}\implies \cfrac{[y- (-3)]^2}{ 6^2}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ b^2}=1
\\\\\\
c^2=a^2+b^2\implies (2\sqrt{10})^2=6^2+b^2\implies 2^2(\sqrt{10})^2=36+b^2
\\\\\\
4(10)=36+b^2\implies 40=36+b^2\implies 4=b^2
\\\\\\
\sqrt{4}=b\implies 2=b\\\\
-------------------------------\\\\
\cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 2^2}=1\implies \cfrac{(y+3)^2}{ 36}-\cfrac{(x- 2)^2}{ 4}=1

3 0
2 years ago
if you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?
Romashka-Z-Leto [24]

Answer:

see below

Step-by-step explanation:

2x+8y=12 3x-8y=11

If we have to solve by substitution, Take the first equation and divide by 2

2x/2 + 8y/2 =12/2

x+4y = 6

Then subtract 4y from each side

x = 6 -4y

Then substitute this into the second equation

This is best solved by elimination

2x+8y=12

3x-8y=11

----------------

5x = 36

x = 36/5

6 0
2 years ago
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