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FrozenT [24]
3 years ago
11

Choose the correct description of the graph of the compound inequality x-2>-3 and 3x<_12

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0
 description of the graph of the compound inequality is, x>-1 and x<-4
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Step by step 6x + 3y = 12
marissa [1.9K]

Answer:

x=4-y/2

Step-by-step explanation:

subtract 3y from both sides

simplify

divide both sides by 6

3 0
3 years ago
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87 pounds to 16 pounds
LekaFEV [45]

Answer:

In explanation.

Step-by-step explanation:

what are you exactly looking for here are some of my ideas.

How many pounds did it drop=?

from 87 to 16 pounds it dropped a total of 71 pounds.



what was the percent increase=?

The percentage of the pound increase is 81.6092.

you calculate this  bu - value 2 by value 1 the divided your answer with value 1 you then times that answer by 100.

Maybe the decimal form,written form,fraction form, of the awnser after you subtract.

decimal form is 0.71

written form is seventy one pounds.

fraction form=71/100 after subtract.

are any of these the things your looking for?

Hope it helps have a great day:)

5 0
3 years ago
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What is the domain of the function graphed below?
DaniilM [7]

Answer:

(-2,4] and [7,α)

Step-by-step explanation:

the domain is open at -2 but closed at 4 and also closed at 7 but open till infinity..

8 0
3 years ago
Compare and contrast the methods you can use to multiply a whole number and a decimal
jek_recluse [69]
What do you mean about what



3 0
3 years ago
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Solve: (-5/6) × (9/20) + (-5/6) × 7/25 = ?​
jonny [76]

\bf \underline{★ How \:to\: do -} \\

Here, we are given with four fractions to multiply two of them and to add two of them. If we add them directly by taking the LCM and adding them is not a similar way. We can clearly observe that in those four fractions, we have two fractions as common i.e, we have two fractions as same. If we have two fractions or numbers as same, we can solve the sum by an other concept called as distributive property. In this property, we multiply the common fraction with the sum of other two fractions. This concept can also be done with fractions as well as integers. So, let's solve!!

\:

\bf \underline{➤ Solution-} \\

{\tt \leadsto \dfrac{(-5)}{6} \times \dfrac{9}{20} + \dfrac{(-5)}{6} + \dfrac{7}{25}}

Group the non-common fractions in bracket.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9}{20} + \dfrac{7}{25} \bigg)}

First we should solve the numbers in bracket.

LCM of 20 and 25 is 100.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9 \times 5}{20 \times 5} + \dfrac{7 \times 4}{25 \times 4} \bigg)}

Multiply the numerators and denominators in the bracket.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45}{100} + \dfrac{28}{100} \bigg)}

Now, write both numerators in bracket with a common denominator.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45 + 28}{100} \bigg)}

Now, add the numerators in bracket.

{\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{73}{100} \bigg)}

Write the numerator and denominator in lowest form by cancellation method.

{\tt \leadsto \dfrac{\cancel{(-5)} \times 73}{6 \times \cancel{100}} = \dfrac{(-1) \times 73}{6 \times 20}}

Now, multiply the numerators and denominators.

{\tt \leadsto \dfrac{(-73)}{120}}

\:

{\red{\underline{\boxed{\bf So, \: the \: answer \: obtained \: is \: \: \dfrac{(-73)}{120}}}}}

3 0
3 years ago
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