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3 years ago

ASAP what is the GCF between 20, 24, and 32?

2 answers:

6 0

The factors of 20 are: 1, 2, 4, 5, 10, 20

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

The factors of 32 are: 1, 2, 4, 8, 16, 32

The greatest common factor is 4.

noname [10]3 years ago

5 0

Answer:

what is the GCF between 20, 24, and 32?

Step-by-step explanation:

You might be interested in

Solve x^2 +13x+12=0 Please answer this

WITCHER [35]

Answer:

x=−1 or x=−12

Step-by-step explanation:

Let's solve your equation step-by-step.

x2+13x+12=0

Step 1: Factor left side of equation.

(x+1)(x+12)=0

Step 2: Set factors equal to 0.

x+1=0 or x+12=0

x=−1 or x=−12

3 0

3 years ago

Read 2 more answers

1. (5 points) At 6pm, ghost A is 5 kilometers due west of ghost B. Ghost A is flying west

zaharov [31]

Answer:

The distance between the ghost changes at 10 pm approximately at a rate of 24.981 kilometers per hour.

Step-by-step explanation:

At first we assume that north and east directions both represent positive quantities. Let suppose that $\vec r_{A,o} = (0\,km,0\,km)$ and $\vec r_{B,o} = (5\,km, 0\,km)$ . If both ghosts moves at constant velocity such that $\vec v_{A} = \left(-15\,\frac{km}{h}, 0\,\frac{km}{h} \right)$ and $\vec v_{B} = \left(0\,\frac{km}{h},20\,\frac{km}{h} \right)$ , then the final positions of both ghosts are, respectively:

Ghost A

$\vec r_{A} = \vec r_{A,o}+t\cdot \vec v_{A}$ (Eq. 1)

Ghost B

$\vec r_{B} = \vec r_{B,o}+t\cdot \vec v_{B}$ (Eq. 2)

Where $t$ is the time, measured in hours.

Then, the equations of motion of each ghost are, respectively:

Ghost A

$\vec r_{A} = (0\,km,0\,km)+t\cdot \left(-15\,\frac{km}{h}, 0\,\frac{km}{h} \right)$

$\vec r_{A} = \left(-15\cdot t, 0)\,\,\,\left[km \right]$

Ghost B

$\vec r_{B} = (5\,km, 0\,km)+t\cdot \left(0\,\frac{km}{h}, 20\,\frac{km}{h} \right)$

$\vec r_{B} = (5, 20\cdot t)\,\,\,\left[km\right]$

Then, the distance between both ghosts is:

$\vec r_{B/A} = (5,20\cdot t)-(-15\cdot t, 0)\,\,\,[km]$

$\vec r_{B/A} =(5+15\cdot t, 20\cdot t)\,\,\,[km]$ (Eq. 3)

The magnitude of the relative is represented by the following Pythagorean identity:

$r^{2}_{B/A} = (5+15\cdot t)^{2}+(20\cdot t)^{2}$

Then, we find the rate of change of the relative distance ( $\dot r_{B/A}$ ), measured in kilometers per hour, by implicit differentiation:

$2\cdot r_{B/A}\cdot \dot r_{B/A} = 2\cdot (5+15\cdot t)\cdot 15+2\cdot (20\cdot t)\cdot 20$

$r_{B/A}\cdot \dot r_{B/A} = 15\cdot (5+15\cdot t)+20\cdot (20\cdot t)$

$\dot r_{B/A} = \frac{75+625\cdot t}{r_{B/A}}$

$\dot r_{B/A} = \frac{75+625\cdot t}{\sqrt{(5+15\cdot t)^{2}+(20\cdot t)^{2}}}$ (Eq. 4)

If we know that $t = 4\,h$ , then the rate of change of the relative distance at 10 PM is:

$\dot r_{B/A} = \frac{75+625\cdot (4)}{\sqrt{[5+15\cdot (4)]^{2}+[20\cdot (4)]^{2}}}$

$\dot r_{B/A} \approx 24.981\,\frac{km}{h}$

The distance between the ghost changes at 10 pm approximately at a rate of 24.981 kilometers per hour.

4 0

4 years ago

Find the number between 30 and 70 that is divisible by 8, and when divided by 5 has a remainder of 1

monitta

30+70÷8÷5-1=
=30.75
hope this helps

7 0

3 years ago

Point B is 1/4 of the way from A-to-C. what are the coordinates of C? A(-4,-5) B (12,6)

Irina18 [472]

Answer:

Step-by-step explanation:

$\overline{AB}=(12-(-4))i+(6+5)j=16i+11j$

Since AB is 1/4 of AC then

$AC = 4 AB\\AC = 4(16i +11j) = 64i+44j$

Now

$\overline{OC}=\overline{OA}+\overline{AC}\\=(-4i -5j) + (64i+44j)\\=60 i +39j$

Therefore C(60,39).

5 0

3 years ago

Solve for x to the nearest tenth...please help me lol

sleet_krkn [62]

Answer:

Step-by-step explanation:

A^2+B^2=C^2 is the pythagorean theorem to find a missing siede of a triangle.

First triangle on the right:

5^2+B^2=10^2

25+B^2=100

B^2=75

B=8.66025404

B=8.7

Second triangle of left:

3^2+B^2=8.7^2

9+B^2=75.69

B^2=66.69

B= 8.16639455

B=8.2

x=8.2

3 0

3 years ago