5 and 2/3 because 51/9= 5.666666667, which .66666667 in fraction form is 2/3
The rule for expressing a radical as a rational exponent is as follows:
![\sqrt[n]{x^y} = x^ \frac{y}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Ey%7D%20%3D%20x%5E%20%5Cfrac%7By%7D%7Bn%7D%20)
So, to find
![\sqrt[3]{27x^2y^3z^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27x%5E2y%5E3z%5E4%7D%20%20)
use that rule.
The cube root of 27 is 3, so the equation will start with 3.

Hope that helps!
The value of k should be 2.
if you plug the y value of the point in the equation for y and do the same with x you should be able to get this answer after fallowing the order of operation.
Answer:
No
Step-by-step explanation:
Because the number 4 repeats itself in a function no numbers repeat themselves
<u>answer</u><u>:</u> 74
<u>explanation</u><u>:</u>
7-3=4
74
+47
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121