To answer this, you will use the area of 900 square yards to determine the distances between the bases. Each side of the square is 30 yards, so it will be 30 yards from 1st to home and from 1st to 2nd.
The distance from home to 2nd is a diagonal in the square (the hypotenuse).
You will use the Pythagorean Theorem to find this distance.
a^2 + b^2 = c^2
30^2 + 30 ^2 = c^2
900 + 900 + c^2
1800 = c^2
The square root of 1800 is approximately 42.4 yards.
The ball travels approximately 42.4 yards.
Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:

You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.
Answer:
Unlike terms
Step-by-step explanation:
If it was 4y and 5y it would be like. Adding the x though makes them unlike terms, you cannot combine them
1.
km=kilometers
kilo=1000
1 km=1000meters
so
1/2km= 1/2 times 1000=1000/2=500meters
2. 1/4 km=1000/4=250 meters
3. 1/5 km=1000/5=200 meters
4. 2/5 km=2000/5=400 meters
5. 3/4 km=3000/4=750 meters
6. 1/8 km=1000/8=125 meters
<span>\(x^2 + ax + b\) factors into \((x + p)(x + q)\), where \(p\) and \(q\) are factors of \(b\) whose sum is \(a\).</span>