Answer:
Life-span.
Explanation:
The Life-span approach to developmental change, as Professor Sharma studies in the exercise, states that change occurs throughout our hole lives, not only in a particular moment or stage of it. Erikson, the first that proposed this system, modified what Freud developed and emphasized the social nature of our development rather than its sexual nature.
Answer:
Students assigned in condition <u>(1) the student was not feeling well after drinking too much </u>are most likely to provide an honest response.
Explanation:
A normal an common situation among young people is to drink or party, so an honest respond would be that they were drinking instead of studying, and getting ready for the exam. They are not likely to obtain an extension after saying this statement, but it certainly can be an honest one.
Answer:
34.83% probability that the proportion of invoices in the sample is less than 18%
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
For a proportion p in a sample of size n, we have that
In this problem, we have that:
So
What is the probability that the proportion of invoices in the sample is less than 18%?
This is the pvalue of Z when X = 0.18. So
has a pvalue of 0.3483
34.83% probability that the proportion of invoices in the sample is less than 18%