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2 years ago

The sum of two numbers is -50. Their difference is - 10. Find the numbers.

Mathematics

2 answers:

True [87]2 years ago

7 0

Answer:

Larger is -30

Smaller is -20

Step-by-step explanation:

-50/2 = -25

difference is -10

add 5 to one number minus 5 from the other

-25 - 5 = -30

-25 + 5 = -20

Hope this helps :)

choli [55]2 years ago

3 0

Answer:

be careful how you answer this

the larger number (y) = - 20

the smaller number (x) = - 30

Think money. Which would you rather be: 20 dollars in the hole or 30 dollars.

Step-by-step explanation:

x + y = -50

<u>x - y = -10</u> Add

2x = - 60 Divide both sides by 2

2x/2 = -60/2 Do the division

x = - 30

=============

-30 - y = - 10 Substitute - 30 for x in the second equation

-30+30- y = -10 + 30 Add 30 to both sides

-y = +20 Divide by -1 on both sides

y = - 20

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2 years ago

If AC = 2, CD = 6, and CE = 3, what is BC?

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Answer:

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2 years ago

Read 2 more answers

Determine the number of real solutions the equation has.

just olya [345]

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2 years ago

Sandra throws an object straight up into the air with initial velocity of 38 ft per square from platform that is 30 ft above the

expeople1 [14]

Answer:

3 seconds.

Step-by-step explanation:

We have been given that Sandra throws an object straight up into the air with initial velocity of 38 ft per second from platform that is 30 ft above the ground.

To find the time it will take for object to hit the ground, we will use formula:

$h(t)=-16t^2+v_0t+h_0$ , where, $v_0$ represents initial velocity and $h_0$ represents initial height.

Upon substituting our given initial velocity and initial height, we will get:

$h(t)=-16t^2+38t+30$

We know that object will hit the ground, when height will be 0, so we will equate object's height equal to 0 and solve for t as:

$-16t^2+38t+30=0$

Divide by 2:

$-8t^2+19t+15=0$

Upon using quadratic formula, we will get:

$t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-19\pm\sqrt{19^2-4(-8)(15)}}{2(-8)}$

$t=\frac{-19\pm\sqrt{361+480}}{-16}=\frac{-19\pm\sqrt{841}}{-16}$

$t=\frac{-19\pm29}{-16}$

$t=\frac{-19-29}{-16},t=\frac{-19+29}{-16}$

$t=\frac{-48}{-16},t=\frac{10}{-16}$

$t=3,t=-\frac{5}{8}$

Since time cannot be negative, therefore, it will take 3 seconds for object to hit the ground.

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2 years ago

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