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2 years ago

8

Write the equation of the line in slope-intercept that has passes through the points and (4, -8). (-3, 27)

1 answer:

Arte-miy333 [17]2 years ago

4 0

Answer:

It's y = -5x + 12 and/or 5x + y = 12

Step-by-step explanation:

(x,y) is really helpful

*I believe that I'm correct, but I would recommend a quick double-check (just like any other math-related question)

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You start with $.50 at the beginning of the year. This amount doubles every month. How much will you have at the end of the 12th

Doss [256]

Take .50 and multiply it by 2 because it doubled. then multiply that by 6 or 12 to get your answer

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2 years ago

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If there's a 9% tax, and the couch is $227.49 what will the total be?

ZanzabumX [31]

Answer

Step-by-step explanation:

227.49 x 1.09 = 247.96

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2 years ago

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PtichkaEL [24]

Answer:

Step-by-step explanation:

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2 years ago

n many population growth problems, there is an upper limit beyond which the population cannot grow. Many scientists agree that t

givi [52]

Answer:

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

Step-by-step explanation:

The logistic function of population growth, that is, the solution of the differential equation is as follows:

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

We use this equation to find the value of r.

In this problem, we have that:

$K = 16, P_{0} = 2, P(50) = 4$

So we find the value of r.

$P(t) = \frac{KP_{0}e^{rt}}{K + P_{0}(e^{rt} - 1)}$

$4 = \frac{16*2e^{50r}}{16 + 2*(e^{50r} - 1)}$

$4 = \frac{32e^{50r}}{14 + 2e^{50r}}$

$56 + 8e^{50r} = 32e^{50r}}$

$24e^{50r} = 56$

$e^{50r} = 2.33$

Applying ln to both sides of the equality

$50r = 0.8459$

$r = 0.017$

So

The differential equation is

$\frac{dP}{dt} = rP(1 - \frac{P}{K}) = 0.017P(1 - \frac{P}{16})$

3 0

2 years ago

Which table shows y as DIRECTLY PROPORTIONAL to x

Furkat [3]

Answer:

Table B

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

<em>Verify table B</em>

For $x=1, y=1/2$ -----> $k=y/x=(1/2)/1=1/2$

For $x=2, y=1$ -----> $k=y/x=1/2$

For $x=3, y=3/2$ -----> $k=y/x=(3/2)/3=1/2$

For $x=4, y=2$ -----> $k=y/x=2/4=1/2$

The values of k are the same

therefore

The table B shows y as DIRECTLY PROPORTIONAL to x

<em>Verify table D</em>

For $x=1, y=3$ -----> $k=y/x=3/1=3$

For $x=2, y=5$ -----> $k=y/x=5/2=2.5$

For $x=3, y=7$ -----> $k=y/x=7/3$

For $x=4, y=9$ -----> $k=y/x=9/4$

the values of k are different

therefore

The table D not shows y as DIRECTLY PROPORTIONAL to x

5 0

2 years ago