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ch4aika [34]
3 years ago
15

HELP PLEASE!! I WILL GIVE BRAINLIEST

Mathematics
1 answer:
NISA [10]3 years ago
6 0
77 feet I according to my calculations :)
You might be interested in
List the integers that satisfy both these inequalities, 2x+9 -12
Flura [38]

Answer:

x < -10.5

Step-by-step explanation:

list the integers that satisfy both these inequalities, 2x+9 <-12

Subtract 9 from  both sides;

2x +9 - 9 < -12-9

2x < -21

x < -21/2

x < -10.5

<em>Hence all the integers are values of x less than 10.5</em>

<em></em>

4 0
2 years ago
if your car gets 26 miles per gallon how much does it cost to drive 420 miles when gas is $2.80 per gallon​
Kitty [74]

Answer:

$45.22

Step-by-step explanation:

The number of miles per gallon can be represented by the ratio:

\frac{miles}{gallon}=\frac{26}{1}

Since we know the unit rate of 26 miles per gallon of gas, we can set up a proportion, or equivalent ratios, to find the number of gallons needed for 420 miles:

\frac{26}{1}=\frac{420}{x}, where 'x' is the number of gallons of gas

cross-multiply and divide:  26x = 420 or x ≈ 16.15 gallons

If gas is $2.80 per gallon, take the total number of gallons needed and multiply by $2.80:

16.15 x $2.80 = $45.22

5 0
3 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
2 years ago
Make 24 using 1,2,2,7
alexdok [17]
7 times 2=14
14 times 2=24
24 times 1=24
5 0
3 years ago
Read 2 more answers
Determine a series of transformations that would map polygon ABCDE onto polygon A’B’C’D’E
zalisa [80]

Answer:

Reflected across x-axis followed by a dilation with a scale factor of 2 about the origin.

Step-by-step explanation:

It's clear from the graph,

Polygon ABCDE is reflected across x-axis then dilated so that it overlaps polygon A'B'C'D'E'

Let's choose a point A having coordinates (-2, -1)

By reflecting point A across x-axis,

Rule to be followed for the reflection,

(x, y) → (x, -y)

By this rule, coordinates of the image point A will be,

A(-2, -1) → A"(-2, 1)

Now point A"(-2, 1) has been dilated by a scale factor = k to form an image points A'(-4, 2).

Rule for the dilation of a point about the origin is,

A"(x, y) → A'(kx, ky)

A"(-2, 1) → A'(-2k, k)

Since, coordinates of point A' are (-4, -2),

Therefore, -2k = -4

k = 2

k = 2

Hence, polygon ABCDE was reflected across x-axis followed by a dilation with a scale factor of 2 about the origin to form polygon A'B'C'D'E'.

3 0
2 years ago
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