Answer (<u>assuming it can be in slope-intercept form)</u>:
y = -x - 1
Step-by-step explanation:
When knowing the slope of a line and its y-intercept, you can write an equation to represent it in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.
1) First, find the slope of the equation, or m. Pick any two points from the line and substitute their x and y values into the slope formula, 
. I chose the points (0, -1) and (-1, 0):
Thus, the slope is -1.
2) Now, find the y-intercept, or b. The y-intercept of a line is the point at which the line crosses the y-axis. By reading the graph, we can see that the line intersects the y-axis at the point (0,-1), therefore that must be the y-intercept.
3) Now, substitute the found values into the y = mx + b formula. Substitute -1 for m and -1 for b:
The data below shows the average number of text messages sent daily by a group of people: 7, 8, 4, 7, 5, 2, 5, 4, 5, 7, 4, 8, 2,
enot [183]
It all depends. You've given us an incredibly vague question.
The outlier could be a number that's low or quite high. Also, outliers
shouldn't really contribute towards the value of the mean, median or
range related to a group of data.
They are called outliers because they are bizarre results or numbers
and should be detached from groups of data. Outliers by definition
are abnormalities or anomalies.
I'd say outliers don't really change anything, unless you actually want
to give them credibility or weight.
Large outliers can inflate the value of means, medians and ranges.
Small outliers will invariably deflate the value of means and medians.
The ODE is separable:
Integrating both sides gives
