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1 answer:
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Answer:
See the answer below
Explanation:
For each heterozygous parent with the genotype BbRr, the possible gametes are: BR, Br, bR, and br. A set of these gametes from one of the parents will be lined up along the top of the Punnet's square while another set from the other parent will be lined up along the side of the square.
The result is shown in the attached image.
