Answer:
Variable rate of change.
Step-by-step explanation:
Plot the points and you'll see that the graph is not a straight line, therefore the rate of change is variable.
The proof is given below. Please go through it.
Step-by-step explanation:
To solve Δ ABC ≅ Δ DBC
From Δ ABC and Δ DBC
AB = BD (given)
AC = CD (given)
BC is common side
By SSS condition Δ ABC ≅ Δ DBC ( proved)
To solve Δ EHF ≅ Δ GHF
Δ EHF and Δ GHF
EH = HG ( given)
∠ EFH = ∠ GFH ( each angle is 90°)
HF is common side
By RHS condition
Δ EHF ≅ Δ GHF
Answer:
There are no solutions for the pair of equations.
The lines are parallel to each other
Step-by-step explanation:
Line Q has a slope of 1/2 and crosses the y axis at 3.
This mean at x=0, y=3
Using the equation of a straight line expression to find the slope
y=mx +c where m is slope and c in the y intercept you can write the equation for Line Q as;

For the Line S , slope is 1/2 and the line crosses the y axis at -2 , which represents the c in the equation y=mx +c
The equation for S will be

Using the graphing tool to plot the two equations for line Q and line S we notice that the lines are parallel .For solutions, they have to intersect.
A negative times a negative is always a positive so the answer would be positive.
Solve for m by simplifying both sides of the equation, then isolating the variable.
m = -2.5