Help please, this is due in 10 mins lol.

Mathematics

1 answer:

Inga [223]3 years ago

8 0

Okbhcoflhfkditditdiitdiyditdikti

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Using a trigonometric ratio to find an angle measure of a right triangle‼️ round to the nearest 10‼️

Verizon [17]

To find the angle x, you are given the triangle side lengths that are opposite and adjacent to the angle. The opposite side is 49 units long. The adjacent side is 24 units long. The trigonometric function that corresponds to the opposite and adjacent legs is tangent.

to find x: $tanx=\frac{49}{24}$

to find an angle using a trigonometric function we must use the inverse function.

$arctan(\frac{49}{24} )=63.90457584$

The angle x, to the nearest tenth of a degree is 63.9 degrees.

5 0

3 years ago

Helpppp!! right answer only pleaseee

hodyreva [135]

Answer:

linear equation

Step-by-step explanation:

it's the only one that matches the description :)

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3 years ago

Read 2 more answers

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$