Answer:
The mass of the exotic fruit is 20 grams.
Step-by-step explanation:
For the system to be in equilibrium,
i. the resultant of all masses must be zero
ii. the total mass on the left of the hanger must be equal to that on the right
Thus,
84 g = 42 g + 42 g
mass of each carrot = 12 g
mass of each mushroom = 10 g
mass of each cherry = 2.5 g
mass of each strawberry = 5 g
So that;
On the left of the hanger,
(2 x 5) + (2 x 10) + 12 = 42
10 + 20 + 12 = 42
42 = 42
On the right of the hanger, let the mass of exotic fruit be represented by x.
x + 12 + 5 + (2 x 2.5) = 42
x + 12 + 5 + 5 = 42
x + 22 = 42
x = 20 g
The mass of the exotic fruit is 20 grams.
Answer:
=268 cm²
Step-by-step explanation:
S=(4×10+4×5+5×10)×2×6×4=268cm²
The surface area of the composite figure = the surface area of the bottom cuboid + the flank area of the top Cuboid
P(n) = 70n - 1500....let me break this down for you
profit = revenue - expenses
so the revenue, what is made from selling tickets.....70n....where n represents the number of tickets....the 70 represents the cost of each ticket.
the 1500 is the expenses. So for them to make a profit, they would have to sell more then $ 1500 worth of tickets.
the price of a single ticket is $ 70 <==
Answer:96
Step-by-step explanation: 6•4^2=16•6=96