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luda_lava [24]
3 years ago
10

(ii) Use the quadratic formula to solve 4x2 +11x-300 = 0.

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0
X=-b+-sqrt (b^2-4ac)/2a
x=-11+-sqrt (11^2-4(8)(-300)/16
x=-11+-sqrt (121+9600)/16
x=-11+-sqrt (9721)/16
x=-11+-98.6/16
x=5.48 or x=-6.85
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Answer:

1 | 38

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Step-by-step explanation:

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6 0
3 years ago
HELP PLEASE........ on these 2​
tester [92]
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3 years ago
How do i Evaluate In 7. ?
Pachacha [2.7K]

Answer:

  (b)  1.95

Step-by-step explanation:

One of the easiest ways to evaluate an arithmetic expression of almost any kind is to type it into an on-line calculator. Many times, typing it into a search box is equivalent.

<h3>Application</h3>

See the attachment for the search box input (at top) and the result. This calculator has the benefit that it <em>always follows the Order of Operations</em> when evaluating an expression. (Not all calculators do.)

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<em>Additional comment</em>

If your math course is asking you to evaluate such expressions, you have probably been provided a calculator to use, or given the requirements for a calculator suitable for use in the course.

There are some very nice calculator apps for phone and tablet. Many phones and tablets already come with built-in calculator apps. For the purpose here, you need a "scientific" or "graphing" calculator. A 4-function calculator will not do.

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Years ago, handheld calculators were not available, and most desktop calculators were only capable of the basic four arithmetic functions. Finding a logarithm required use of a table of logarithms. Such tables were published in mathematical handbooks, and extracts of those often appeared as appendices in math textbooks used in school.

3 0
2 years ago
what is the sum of the first five ferms of a geometric series with a1=10 and r=1/5? express your answer as an important fraction
mote1985 [20]
The sum of any geometric sequence, (technically any finite set is a sequence, series are infinite) can be expressed as:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=term number

Here you are given a=10 and r=1/5 so your equation is:

s(n)=10(1-(1/5)^n)/(1-1/5)  let's simplify this a bit:

s(n)=10(1-(1/5)^n)/(4/5)

s(n)=12.5(1-(1/5)^n) so the sum of the first 5 terms is:

s(5)=12.5(1-(1/5)^5)

s(5)=12.496

as an improper fraction:

(125/10)(3124/3125)

390500/31240

1775/142
6 0
3 years ago
Factor x^3−5x^2−25x+125
UkoKoshka [18]
(x-5)^2 . ( x+5)
=( x^2 - 10x + 25) . ( x+ 5)
=x^3 + 5x^2 - 10x^2 -50x + 25x + 125
= x^3 - 5x^2 -25x +125
5 0
3 years ago
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