According to the problem we start with 6000 gal of E10 which means there is 10% of ethanol in this 6000, with ths information we can calculate the amount of ethanol already in the mixture:

The relationship between ethanol and total fluid can be represented like this:

Based on this relationship we can build the one that we are looking for:


the total solution will be:

where X is the E5 solution volume
and the TotalEthanol would be:

where E5ethanol (5% Ethanol 95% Gasoline) would be:

Now replacing in the relationship we found before:

Solving for X:

We should mix 1500 gal of E5 to make an E9 mixture
Step-by-step explanation:
210÷3×2=140 (140)CD
210-140=70 (70)left
70÷4×1=17.50 (17.50)food
70-17.50=52.50 (52.50)left
Answer:
a1=3, a2=6, a3=12, a4=24, a5=48
Step-by-step explanation:
a7=a*r^6=192
a10=a*r^9=1536, r^3=8, r=2 and a=3
a1=3, a2=6, a3=12, a4=24, a5=48
Answer:
1.5 I'm pretty shure
Step-by-step explanation: