2 years ago

HELP WITH ALL PLSSSSSSSSS

Mathematics

2 answers:

igor_vitrenko [27]2 years ago

6 0

Step-by-step explanation:

hold on I'm. going to help you with this

svlad2 [7]2 years ago

5 0

I need answers I csnt help you my brotha, would appreciate if you could give me a thumbs up

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Quadrilateral ABCD is a square and the length of BE¯¯¯¯¯ is 6 cm.

SashulF [63]

BE = 6cm
BD = 12 cm
For a square, the diagonal are equal

so :::
AC = BD = 12 cm

Done :)

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3 years ago

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A square prism measuring 6 km along each<br> edge of the base and 5 km tall.

Alex

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What number should be placed in the box to help complete the division calculation?

Vinvika [58]

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a bag of marbles contains 8 red marbles, 4 blue marbles, and 5 white marbles. tom picks a marble at random. is it more likely th

iVinArrow [24]

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It is more likely of a diffrent color.

Step-by-step explanation:

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2 years ago

The Lacrosse booster club is holding a raffle for a fundraiser. They will sell 100 tickets for $5 each and select 4 winners. All

Nadusha1986 [10]

Answer:

<h2>There are 3,921,225 ways to select the winners.</h2>

Step-by-step explanation:

This problem is about combinations with no repetitions, because the same person can't win four times. It's a combinaction because the order of winning doesn't really matter.

Combinations without repetitions are defined as

$C_{n}^{r} =\frac{n!}{r!(n-r)!}$

Where $n=100$ and $r=4$ .

Replacing values, we have

$C_{100}^{4} =\frac{100!}{4!(100-4)!}=\frac{100!}{4! 96!}=\frac{100 \times 99 \times 98 \times 97 \times 96!}{4! \times 96!}= \frac{94,109,400}{24}= 3,921,225$

Therefore, there are 3,921,225 ways to select the winners.

Additionally, as you can imagine, the probability of winning is extremely low, it would be 3,921,225 to 1.

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2 years ago