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Shkiper50 [21]
3 years ago
10

A piepie is divided into 2020 equal pieces. GlennGlenn and SophieSophie each ate one fourth 1 4 of the piepie on MondayMonday. T

he next​ day, SophieSophie ate one fifth 1 5 of the piepie that was leftover. How many of the pieces of the original piepie ​remain? Explain your reasoning. ​Together, GlennGlenn and SophieSophie ate one fourth 1 4 ​piece(s) on MondayMonday​, and SophieSophie ate one fifth 1 5 ​piece(s) the next day. To find the number of pieces that​ remain, add these numbers to the total number of pieces.​ So, 0.450.45 pieces of the original piepie remain.
Mathematics
1 answer:
andriy [413]3 years ago
3 0

Answer:

Pieces remaining =  1 - (1/4 + 1/4) - (1/2 x1/5) = 1/2 - (1/2 x1/5) = 1/2 - 1/10 = 4/10

Therefore, 4/10 x 20 = 8 pieces.

Step-by-step explanation:

Sophie ate 1/4 = 5 pieces

Glenn ate 1/4 = 5 pieces

Remaining pieces = 20 - 5 - 5 = 10 pieces

On Monday, Sophie ate = 1/5 x 10 = 2 pieces

Therefore, remaining pieces = 10 - 2 pieces = 8 pieces

Sophie and Glenn consumed half of the pie the first day.  This is equal to 10 pieces.  The remaining pieces will be 10.  If, on Monday, Sophie ate 1/5 of 10 pieces, representing 2 pieces, the number left over is 10 Minus 2, which equals 8 pieces.

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The diagram represents two statements: p and q.
suter [353]

Answer:

The Region A represents p

The Region B represents p ∧ q

The Region C represents q

Step-by-step explanation:

The figure is as follows :

Given - The diagram represents two statements: p and q.

To find - Which represents regions A, B, and C?

A) p v q

B) p -> q

C) q ^ p

D) q -> p​

Solution -

From the figure, we can see that,

The Region A represents p

The Region B represents p ∧ q

The Region C represents q

The truth table is as follows :

p         q        p ∧ q

T         T           T

T          F           F

F          T           F

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5 0
3 years ago
What operation is used to make a prediction using a probability
Dmitry_Shevchenko [17]

Answer:

Division

Step-by-step explanation:

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8 0
4 years ago
Read 2 more answers
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1
Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

<h2>_____________________</h2>

4 0
3 years ago
2. A lunch stand makes s.75 profit on each chef's salad and $1.20 profit on each Caesar salad. On a typical weekday, it sells be
kow [346]

Let's let

<u>x = the number of chef salads, x>=0</u>

<u>y = the number of Caesar salads, y>=0</u>

The constrains are:

40 <= x <= 60

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x + y <= 100

The objective function here is F(x, y) = 0.75x + 1.20y

The corner points are (40, 35),  (60, 35), (60, 40), (50, 50) and (40, 50).

F (40, 35) = 0.75*40 + 1.20*35 = $72

F (60, 35) = 0.70*60 + 1.20*35 = $84

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F (50, 50) = 0.75*50 + 1.20*50 = $97.50

F (40, 50) = 0.75*40 + 1.20*50 = $90

Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.

8 0
4 years ago
a prayng mantis is an interesting insect that can rotate its head 180 degrees.Suppose the praying mantis at the right is 10.5 ce
cricket20 [7]
The fact that it can turn its head 180 degrees is just extra information. They tell us that it is 10.5 cm long. What they're asking for is the length in a mixed number, so 10.5 as a mixed number.
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