The number of days of not leap years is 365.
So, the number of different variations of birthdays for 4 people is 365 * 365 * 365 * 365 = (365)^4
The probability that all of them be one specific day is 365 / (365)^4 = 1 / (365)^3 ≈ 0.00000002.
Answer: 0.00000002
4+6+6+2=18(balls)
Another way 1)4+6=10(balls)-green and blue
2)6+2=8(balls)-green and blue
3)10+8=18(balls)-total probability
Answer: 4). A = (b1 + b2)h/2
5).
A = (b x h)/2
6). A = b x h
7). A = b x h = 65 x 50 = 3250 ft^2
8). A = (b x h)/2 = (12 x 18)/2 = 108 inches^2
9). A = (b1 + b2)h/2 = (15 + 7)4/2 = 44m^2
2/3 = 66%
2/4 = 50%
Therefore, 2/3 is greater
