Rewrite the system of equations in matrix form.

This system has a unique solution
so long as the inverse of the coefficient matrix
exists. This is the case if the determinant is not zero.
We have

so the inverse, and hence a unique solution to the system of equations, exists as long as m ≠ -4.
Answer:
144
Step-by-step explanation:
Answer:
-4
Step-by-step explanation:
7w + (-11w)
Postive negative negative
7w-11w
= - 4
Answer:
Step-by-step explanation:earn vocabulary, terms, and more with flashcards, games, and other study tools. ... term with highest exponent determines how the function behaves divide by ... lim x→c ( f(x)/ g(x) ) = L/M if M≠0 ... the function oscillates and has no limit ... Image: Infinite discontinuity ... y- y₁= m (x-x₁) ...
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