Answer:
Line s and Line t are parallel.
Step-by-step explanation:
Now, we know that angles 1 and 2 are congruent, because they have the same angle measures. Now, looking at their positions, we can see that they are alternate exterior angles.
By the converse of the Alternate Exterior Angle, (I do not remember exactly how the theorem went) if two lines are cut by a transversal and have congruent alternate exterior angles, then the lines are parallel. Using this theorem, we can find that lines s and t are parallel, because they are cut by a transversal and their alternate exterior angles are congruent.
I hope you find my answer and explanation to be helpful. Happy studying.
I've attached a plot of one such cross-section (orange) over the region in the x-y plane (blue), including the bounding curves (red). (I've set
for this example.)
The length of each cross section (the side lying in the base) has length determined by the horizontal distance
between the y-axis
and the curve
. In terms of
, this distance is
. The height of each cross section is twice the value of
, so the area of each rectangular cross section should be
.
This means the volume would be given by the integral
What is the question? If you are only trying to expand the
expression then the answer would be:
1/4 (5y-3)+ 1/16 (12y+17)
(5y/4) – (3/4) + (12y/16) + (17/16)
1.25y – 0.75 + 0.75y + 1.0625
2y + 0.3125
If you are trying to find for y, then you forgot to equate
it to 0, that is:
2y + 0.3125 = 0
2y = -0.3125
<span>y = 0.15625</span>
Answer: 3v^2w^2 + 10v^2w^3 (or the first option on the screen)
