All categories

3 years ago

–3 = –2x2 + 2x

Mathematics

2 answers:

wel3 years ago

4 0

Answer:

Determine the next step for solving the quadratic equation by completing the square.

0 = –2x2 + 2x + 3

–3 = –2x2 + 2x

–3 = –2(x2 – x)

–3 + = –2(x2 – x + )

StartFraction negative 7 Over 2 EndFraction = –2(x – StartFraction 1 Over 2 EndFraction)2

StartFraction 7 Over 4 EndFraction = (x – StartFraction 1 Over 2 EndFraction)2

The two solutions are Plus or minus StartFraction StartRoot 7 EndRoot Over 2 EndFraction

-7/2 = -2(x - ½)²

Step-by-step explanation:

0 = –2x^2 + 2x + 3

Subtract 3 from each side

-3 = –2x^2 + 2x

Factor out the -2

-3 =- 2(x^2 -x)

Take the coefficient of x and divide by 2 and square it

-1 /2 = -1/2 ^2 = 1/4

Add it to each side Remember the -2 on the outside so we need to multiply it by -2

-2 *1/4 = -1/2

-3 -1/2= -2(x^2 -x +1/4)

-7/2 = -2(x^2 -x +1/4)

-7/2 = -2(x-1/2)^2

7/2 = -2(x - ½)²

just olya [345]3 years ago

3 0

Answer:

-1/2

1/4

1/2

Step-by-step explanation:

in that order on edgenuity

You might be interested in

Lucy kicks a shuttlecock into the air from a height of 0.6 feet

SpyIntel [72]

Answer:

4.6 feet

Step-by-step explanation:

The equation is:

$h=-16t^2+vt+s$

Where

v is initial velocity (given as 16)

s is initial height (given as 0.6)

Substituting, we can write:

$h=-16t^2+16t+0.6$

This is a quadratic equation of the general form: $at^2+bt+c$

Which we can conclude the coefficients to be:

a = -16

b = 16

c = 0.6

The max height occurs at the value: $t=-\frac{b}{2a}$

So, max height occurs at:

$t=-\frac{16}{2(-16)}\\t=0.5$

We will get the max height if we put t = 0.5 into the original equation. So that would be:

$h=-16t^2+16t+0.6\\h=-16(0.5)^2+16(0.5)+0.6\\h=4.6$

Max Height = 4.6 feet (occurs at t = 0.5 seconds)

8 0

4 years ago

There are 4 teams in a basketball league. Each team plays each of the other teams three times. How many games are played?

svetlana [45]

12 each that is the answer

8 0

4 years ago

Read 2 more answers

P(x)equals=R(x)minus−C(x). Given R(x)equals=59 x minus 0.3 x squared59x−0.3x2 and Upper C left parenthesis x right parenthesi

Deffense [45]

Answer:

$P(x)=-0.3x^2+56x-14$

Step-by-step explanation:

The given functions are

$R(x)=59x-0.3x^2$

$C(x)=3x+14$

It is given that

$P(x)=R(x)-C(x)$

Substitute the values of given functions in the above equation.

$P(x)=59x-0.3x^2-(3x+14)$

$P(x)=59x-0.3x^2-3x-14$

Combine like terms.

$P(x)=-0.3x^2+(59x-3x)-14$

$P(x)=-0.3x^2+56x-14$

Therefore, the required function is $P(x)=-0.3x^2+56x-14$ .

4 0

4 years ago

Factors of 36 that add to -15

egoroff_w [7]

Whats the problem so i can solve for the whole in tire problem

4 0

4 years ago

X+3y=5 2x-3y=1 substitution method

Dafna1 [17]

Simplify the right side.
x = -2x + 6
y = $\frac{2x}{3} - \frac{1}{3}$

5 0

3 years ago