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amid [387]
4 years ago
11

Lucy kicks a shuttlecock into the air from a height of 0.6 feet

Mathematics
1 answer:
SpyIntel [72]4 years ago
8 0

Answer:

4.6 feet

Step-by-step explanation:

The equation is:

h=-16t^2+vt+s

Where

v is initial velocity (given as 16)

s is initial height (given as 0.6)

Substituting, we can write:

h=-16t^2+16t+0.6

This is a quadratic equation of the general form:  at^2+bt+c

Which we can conclude the coefficients to be:

a = -16

b = 16

c = 0.6

The max height occurs at the value:  t=-\frac{b}{2a}

So, max height occurs at:

t=-\frac{16}{2(-16)}\\t=0.5

We will get the max height if we put  t = 0.5  into the original equation. So that would be:

h=-16t^2+16t+0.6\\h=-16(0.5)^2+16(0.5)+0.6\\h=4.6

Max Height = 4.6 feet   (occurs at t = 0.5 seconds)

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