Answer :The Cu ion is the metal.
• The copper (II) ion is the Cation
• The two chloride ions are the Anions
Explanation:
Answer:
50
Explanation:
There are actually 58, but the closest approximation here is 50
Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.
Answer:
Concentration gradient
Explanation:
Concentration gradient of the ions across the membrane generates the membrane resting potential.
Concentration gradient means that there is unequal distribution of the ions on different sides of membrane. For example, the concentration of K ions is much higher within the cell then out of the cell. Opposite is with the Na ions. When ions move from the area of their higher concentration to the are with the lower concentration, we say they move down the gradient or diffuse (no energy required). On the other hand, movement of ions against their gradient means that this process requires energy and involves protein pumps.
<span>Dens (odontoid process) Hope this helps.</span>
