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Cerrena [4.2K]
3 years ago
10

I really need an a answer again Srry for wasting ur time... but I need an answer quick

Mathematics
1 answer:
defon3 years ago
5 0

Answer:

400m

7000000km

25000m

Step-by-step explanation:

Meter to Kilometer is x1000

kilometer to meter is ÷1000

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Your answer is B Hope I helped :)

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A jet’s speed in still air is 240 mph. One day it flew 700 miles with a tailwind (the wind pushing it along) and then returned t
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Speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

As given in the question,

Given data:

Jet speed in still air = 240mph

Let x be the speed of the wind.

Speed with tail wind = 240 +x

Distance covered with tail wind = 700miles

Time taken by jet with tail wind

= Distance/ speed

= 700 / (240 +x)  __(1)

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Distance covered against the wind = 700miles

Time taken by jet against the wind

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Total time taken is 6 hours

[700 / (240 +x)] + [700 / (240 - x)] = 6

⇒ 700( 240 -x + 240 + x) = 6 (240 +x)(240 - x)

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⇒ x² = 57600 - 56000

⇒ x² = 1600

⇒ x = √1600

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Therefore, speed of the wind for jet speed in still air 240mph and jet covers 700 miles with tailwind and same distance against the wind in total time of 6 hours is equal to 40mph.

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The answer is y=-2x+6

We know the slope of the given equation is -2. A parallel line must have the same slope as the original function. So if we plug in the coordinates and the slope into the point slope formula we get y=-2x +6

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