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Doss [256]
3 years ago
12

A circle has a radius of length r. If you mark off an arc on the circle of length 3r. What is the measurment of of the angkebtha

t sub tends the arc?
A.3 radians
B. 3piR radians
C. 3r radians
D. 3pi radians
Mathematics
2 answers:
MrMuchimi3 years ago
4 0

Answer:

A. 3 radians.

Step-by-step explanation:

A circle arc is a portion of a circle. And the formula of the length of arc with the angle in radians is:

S=R.\beta, where:

S: The arc length.

R:Radius of the circle.

\beta :Angle in radians.

Then we know that the radius of the circle is R=r, and the arc length is S=3r. Then using the arc length formula, the angle that subtends the arc is:

\beta =\frac{S}{R}

\beta =\frac{3r}{r} \\\beta =3 radians

Then the correct option is letter A.

katrin2010 [14]3 years ago
3 0
The appropriate choice is ...
  A. 3 radians

_____
Arc length (s) is given in terms of radius (r) and central angle (θ) in radians by the formula
  s = rθ

When you substitute your given information, you have
  3r = rθ
Dividing by r gives
  θ = 3 . . . . . . . radians
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pochemuha

Answer: She started with $160.

It will take 6 weeks before she has less than half of what she originally invested.

Step-by-step explanation:

If her money is decreasing in value by 11% each week, it means that the rate at which it is decreasing is exponential.

We would apply the formula for exponential decay which is expressed as

A = P(1 - r)^t

Where

A represents the value of the investment after t weeks.

t represents the number of weeks.

P represents the initial value of the investment.

r represents rate of depreciation.

From the information given,

A = $142.40

r = 11% = 11/100 = 0.11

t = 1

Therefore

142.40 = P(1 - 0.11)^1

142.40 = P(0.89)

P = 142.4/0.89

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For her to have half of what she invested originally, then

80 = 160(0.89)^t

80/160 = (0.89)^t

0.5 = (0.89)^t

Taking log of both sides to base 10

Log 0.5 = log0.89^t = tlog0.89

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t = - 0.3010/- 0.051

t = 5.9

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5 0
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