D because for a sequence you can't have a -1st term so b is out and a and c mean the same thing so neither of them can be the answer
Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
3a+7+2a and 7a+5. These expressions are not equivalent. 5a+7 does not equal 7a+5.
Replace all the x's in the equation with -5. f(5)=(5)2-5+2. > 10-5+2 > 5+2= 7
The Answer is 7
