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3 years ago

11

The square below repersents one whole express the shaded area as a fraction, a decimal, and a percent of the whole

1 answer:

lord [1]3 years ago

3 0

Because there are 10 parts in the whole and 2 are shaded, the square can be represented as 2/10 shaded. this can be simplified to 1/5 since the numerator and denominator are both divisible by 2. to convert 1/5 to a decimal, we divide 1 by 5, which results in .2, which we can then convert to a percentage by moving the decimal place two times to the left. therefore, as a percent, the square is shaded 20%.

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P + 5 = 15 help meeeeeeeeeeeeee

Viktor [21]

Answer:

p=10

Step-by-step explanation:

subtract 5 on both sides and you'll get p=10 :]

8 0

3 years ago

The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the

dolphi86 [110]

Answer:

Step-by-step explanation:

let the smaller square be A, and the side is a

larger square is B, the side is a+3

Area(A)=a^2

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a^2+(a+3)^2=425 in^2

a^2+a^2+6a+9=425

2a^2+6a=425-9

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6 0

3 years ago

Which expression is equivalent to 5-8

MAXImum [283]

It’s equivalent to 10/16 and 40/64

3 0

3 years ago

Timothy built a base for a circular tabletop. The base can support a tabletop with a radius of at least 6 inches, but not more t

neonofarm [45]

Let

r------> the radius of the circular tabletop

we know that

$r\geq 6\ in$

$r\leq23\ in$

so

$6\ in \leq r \leq 23\ in$

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$A=\pi r^{2}$

where

r is the radius of the circle

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we know that

the smallest possible area of the tabletop is for $r=6\ in$

Substitute the value of r in the formula

$A=\pi 6^{2}$

$A=113.09\ in^{2}$

Round to the nearest whole square inch

so

$A=113\ in^{2}$

therefore

<u>the answer part a) is </u>

the smallest possible area of the tabletop is $113\ in^{2}$

<u>Part b)</u> What is the largest possible area of the tabletop that will fit on Timothy’s table base?

we know that

the largest possible area of the tabletop is for $r=23\ in$

Substitute the value of r in the formula

$A=\pi 23^{2}$

$A=1,661.90\ in^{2}$

Round to the nearest whole square inch

so

$A=1,662\ in^{2}$

therefore

<u>the answer part b) is </u>

the largest possible area of the tabletop is $1,662\ in^{2}$

7 0

4 years ago

Read 2 more answers

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Stolb23 [73]

Answer:

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Step-by-step explanation:

combine like terms

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8 0

3 years ago