Answer:
3.4 is the answer i think
Step-by-step explanation:
Answer:
R=10
Step-by-step explanation:
-2×-3=6
R=5×2
=10
I think answer should be c. Please give me brainlest let me know if it’s correct or not okay thanks bye
Given :
The diagonals of rhombus ABCD intersect at E.
∠CAD = 20°.
To Find :
The angle ∠CDA.
Solution :
We know, diagonals of a rhombus bisects each other perpendicularly.
So, ∠DEA = 90°.
In triangle ΔEAD :
∠EAD + ∠AED + ∠EDA = 180°
20° + 90° + ∠EDA = 180°
∠EDA = 70°
Now, we know diagonal of rhombus also bisect the angle between two sides .
So, ∠CDA = 2∠EDA
∠CDA = 2×70°
∠CDA =140°
Therefore, ∠CDA is 140°.
Answer:
Step-by-step explanation:
Given
Point (4,-5)
Required
Determine the line equation
From the question, we understand that the line is parallel to
This implies that they have the same slope, m
A linear equation is:
Where
By comparison: and
Next, we determine the line equation using:
Where
and
Hence,
<em>Option C is correct</em>
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