Answer:
6x^2 -2x
Step-by-step explanation:
As written, the constant terms in the first factor cancel each other. The distributive property is used to perform the multiplication:
(3x^2 +1 -1 -x)(2) = (3x^2 -x)(2) = (3x^2)(2) -x(2)
= 6x^2 -2x
Answer:
x² - 2x - 2
By Completing the Square....
x² - 2x + 1² - 2 - 1²
(x - 1)² - 3 .....
Hope it helps.
The third term of the expansion is 6a^2b^2
<h3>How to determine the third term of the
expansion?</h3>
The binomial term is given as
(a - b)^4
The r-th term of the expansion is calculated using
r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)
So, we have
3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)
Evaluate the sum and the difference
3rd term = C(4, 2) * (a)^2 * (-b)^2
Evaluate the exponents
3rd term = C(4, 2) * a^2b^2
Evaluate the combination expression
3rd term = 6 * a^2b^2
Evaluate the product
3rd term = 6a^2b^2
Hence, the third term of the expansion is 6a^2b^2
Read more about binomial expansion at
brainly.com/question/13602562
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