Find the median of the first and third quartiles81, 69 ,90, 79, 59, 125, 95, 116, 183, 97, 92, 50, 122, 55, 9250, 55, 59, 69, 79, 81, 90, 92, 92, 95, 97, 116, 122, 125, 183.The first quartile: 50, 55, 59, 69, 79, 81, 90: median of the first quartile is 69The third quartile: 92, 95, 97, 116, 122, 125, 183: median of the third quartile is 116.The interquartile range is the difference between the median of both the first and third quartile: which is 116 - 69 = 47.There are no outliers in this set of data

4 0

2 years ago

Out triangle-shaped pennants on the first day of school. If each pennant has a base of 5 inches and a height of 12 inches, what

brilliants [131]

Answer:

Area of the penny = 30 square inches

Step-by-step explanation:

Out triangle-shaped pennants on the first day of school. If each pennant has a base of 5 inches and a height of 12 inches, what is the area of each pennant in square inches?

The pennant is triangular in shape. Hence:

Area of a Triangle = 1/2× Base × Height

Base of the pennant = 5 inches

Height = 12 inches

Area of the pennant = 1/2 × 5 inches × 12 inches

= 30 square inches

3 0

3 years ago

Another poem i made just now hope yall like it

dolphi86 [110]

Answer:

that is so sad but thank you for the poem!!!

Step-by-step explanation:

547588485858745875484585468568686854548 x 575747754757757575598844888=3.1527284e+65

7 0

3 years ago

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