Answer:
The answer is;
4^3/10 • x^9/10 •y^3/5
Step-by-step explanation:
We want to express the expression in the bracket in radical form;
(4x^3y^2)^3/10
What we shall do here is to multiply all the powers of the terms in the bracket by 3/10
So we shall have;
4^3/10 • x^(3*3/10) * y^(2*3/10)
= 4^3/10 • x^9/10 • y^3/5
15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
Given that, suppose we want to choose 5 objects, without replacement, from 15 distinct objects.
<h3>What is a permutation?</h3>
A permutation is a mathematical calculation of the number of ways a particular set can be arranged, where the order of the arrangement matters.
Now,
= 13!/(13-5)!
= 13!/8! = 13x12x11x10x9= 1287 x 120 = 15,444
Therefore, 15444 ways we can choose 5 objects, without replacement, from 15 distinct objects.
To learn more about the permutation visit:
brainly.com/question/1216161.
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Y = -6x + 2 . . . . . . . . (1)
-12x - 2y = -4 . . . . . . (2)
Putting (1) into (2), we have
-12x - 2(-6x + 2) = -4
-12x + 12x - 4 = -4
-4 = -4
Therefore, the system has infinite number of solutions.
Answer: (6 x 2) - (4 x 5) + (12 / 4)
Answer:
(7*100) can be written as 7*10^2
4 * / 100 i don’t know
if it was 4 * 100 then it’s 4*10^2
if it was divided then it’s 4*10^-2
8* 1/1000 = 8/1000 = 8*10^-3
add together to get 1.100008 * 10^3 (if it was 4*100)
or 7.00048 * 10^2 ( if it was 4/100)