To find the circumference you do 2x3.14 times radius and for the area you do 3.14 times the radius^2 area for a would be 78.5mm and circumference would be 31.4mm and for b the area is 113.04in and circumference is 37.68
36 ...........................
A) 2 units
B) yes
For A) |5-3|=|2|=2 is the distance from his house to school.
For B)
The distance from his house to school is 2 units; the distance from school to the grocery store is |3--9|=|12|=12. The total distance is 2+12 = 14.
The distance from his house to school is 2 units; the distance from school to the community center is |-4-6|=|-10|=10. The total distance is 2+10 = 12.
The distance from the house to the school to the grocery store is greater.
Answer:
34.5 units²
Step-by-step explanation:
There are methods for finding the area of a polygon using arithmetic on the coordinates. Here, it is probably more convenient to cut the figure into two triangles and a trapezoid and figure the areas of those.
A line from (-5, 1) to (1, 1) will create a triangle above that line with base 6 and height 3. Its area will be ...
A = 1/2·b·h = 1/2·6·3 = 9 . . . units²
Similarly, a line from (1, 1) to (1, -2) will create a triangle to the right of that line with base 3 and height 4. Its area will be ...
A = 1/2·b·h = 1/2·3·4 = 6 . . . units²
The remaining trapezoid has top base 6, bottom base 7, and a height of 3. Its area will be ...
A = 1/2·(b1+b2)·h = 1/2·(6 +7)·3 = 39/2 = 19.5 . . . units²
Then the total area of the figure is ...
(9 + 6 + 19.5) units² = 34.5 units²
Answer:
Hector's kite is 61.84 feet from the ground.
Step-by-step explanation:
The angle of elevation of the kite is 42°15’30” when converted to decimals, it is 
≅ 
Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,
Sin θ = 
Sin = 
⇒ x = 86 x Sin
= 86 x 0.6725
= 57.835
x ≅ 57.84 feet
The height of Hector's kite from the ground = x + 4
= 57.84 + 4
= 61.84 feet
