Answer:
Step-by-step explanation:
A'B' is 1/2 times the AB as the scale factor is 1/2.
<u>Find the length of AB using distance formula.</u>
- AB =

<u>And find A'B':</u>
- A'B' = 1/2*2

Correct choice is A
<span> 80/-40=-40/20=-2,
the sequence: 80, -40, 20 is a geometric sequence
its general formula is Vn+1 = q Vn, where q= -2,
if we put </span>Vn+1 = f(x)
<span> Vn = x
so we have f(x)= -2x so the graph that represents the sequence is graph of linear equation
</span>
Answer:
m = -7/2
Step-by-step explanation:
(y2-y1) / (x2-x1)
->
(-5 - 2) / ( -1 -3)
= -7/2
hope that helps :D