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vitfil [10]
3 years ago
8

Joseph has 213 coins in a jar. All

Mathematics
1 answer:
Kamila [148]3 years ago
8 0

Answer:

the answer I take was 213+42.15=255.15 je have on each

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Find the slope of the line through<br> (-11,8),(-11, -17)
Rom4ik [11]

Answer:

Undefined or Infinity

Step-by-step explanation:

(x1,y1)=(-11,8)

(x2,y2)=(-11,-17)

Slope = (y2-y1)/(x2-x1)

= (-17-8)/(-11-(-11))

= -25/0

= Undefined

5 0
3 years ago
Explain how mental math can be used to estimate a 15% tip on a taxi ride that costs $23.25 Find the tip using that method. Halp
gizmo_the_mogwai [7]

Answer:

$3.4875

Step-by-step explanation:

AS the ride is completed and according the rule the person have to give a tip on the total taxi ride

according to the given

tip given 15%

Total ride cost = $23.25

To find is the total tip given in dollars

Solution:

Total tip in dollars = 15 % of total ride cost

Putting the values of the given

Total tip in dollars = 15 % of 23.25

it can be written as

                             = \frac{15*23.25}{100}

                              =\frac{348.75}{100}

                               =$ 3.4875

So the total tip would be $3.4875

7 0
3 years ago
Customers arrive at a service facility according to a Poisson process of rate λ customers/hour. Let X(t) be the number of custom
mash [69]

Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

W_1,W_2... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))

= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}

=  1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

=  1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

Now P(X(s) \leq 0) = P(X(s) = 0)

(b)  We can Determine the conditional mean E[W3|X(t)=5] as follows;

E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\  = 1- P (X(s) \leq 2 | X (t) = 5 )  \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}

Now; P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)

(c) Determine the conditional probability density function for W2, given that X(t)=5.

So ; the conditional probability density function of W_2 given that  X(t)=5 is:

f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 )  \\ \\  = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)

7 0
4 years ago
Consider th following formula used to find a cone v= 3.14r^2 h/3
lys-0071 [83]
Here's the volume formula (and the area formula) typed a little neater than that.
(I'm guessing you forgot to type in your question?)

7 0
3 years ago
I am not able to solve this question​
Alexxx [7]

Answer:

C

Step-by-step explanation:

join my stream for an explanation

(ChildofHermes)

please mark brainliest

im only streaming for 15 more hours

5 0
2 years ago
Read 2 more answers
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