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Vaselesa [24]
3 years ago
7

I’m extremely stuck on this, please help

Chemistry
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

ice: 2,100 J/(kg·K)

water: 4,200 J/(kg·K)

water vapor: 2,000 J/(kg·K)

basalt: 840 J/(kg·K)

granite: 790 J/(kg·K)

aluminum: 890 J/(kg·K)

iron: 450 J/(kg·K)

copper: 380 J/(kg·K)

lead: 130 J/(kg·K)

Explanation:

Specific heat is the amount of thermal energy you need to supply to a sample weighing 1 kg to increase its temperature by 1 K.

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What is true about all chemical equations?<br> Links are reported
Vanyuwa [196]

Answer:Your answer is A

Explanation:

Hope this helps ツ

6 0
3 years ago
Calculate the electric double layer thickness of a alumina colloid in a dilute (0.1 mol/dm3) CsCI electrolyte solution at 30 °C.
Ad libitum [116K]

Explanation:

The given data is as follows.

    Concentration = 0.1 mol/dm^{3}

                             = 0.1 \frac{mol dm^{3}}{dm^{3}} \frac{10^{3}}{dm^{3}} \times \frac{6.022 \times 10^{23}}{1 mol} ions

                             = 6.022 \times 10^{25} ions/m^{3}

               T = 30^{o}C = (30 + 273) K = 303 K

Formula for electric double layer thickness (\lambda_{D}) is as follows.

            \lambda_{D} = \frac{1}{k} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}

where, n^{o} = concentration = 6.022 \times 10^{25} ions/m^{3}

Hence, putting the given values into the above equation as follows.

                 \lambda_{D} = \sqrt \frac{\varepsilon \varepsilon_{o} K_{g}T}{2 n^{o} z^{2} \varepsilon^{2}}                    

                          = \sqrt \frac{78 \times 8.854 \times 10^{-12} c^{2}/Jm \times 1.38 \times 10^{-23}J/K \times 303 K}{2 \times 6.022 \times 10^{25} ions/m^{3} \times (1)^{2} \times (1.6 \times 10^{-19}C)^{2}}  

                         = 9.669 \times 10^{-10} m

or,                     = 9.7 A^{o}

                          = 1 nm (approx)

Also, it is known that \lambda_{D} = \sqrt \frac{1}{n^{o}}

Hence, we can conclude that addition of 0.1 mol/dm^{3} of KCl in 0.1 mol/dm^{3} of NaBr "\lambda_{D}" will decrease but not significantly.

7 0
3 years ago
Write a net ionic equation for the overall reaction that occurs when aqueous solutions of nitrous acid and sodium hydroxide are
Bess [88]

Answer:

H+(aq) +  OH-(aq) → H2O(l)

Explanation:

Step 1: Data given

nitrious acid = HNO3

sodium hydroxide = NaOH

Step 2: The unbalance equation

HNO3(aq) + NaOH(aq) →NaNO3(aq) + H2O(l)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will , after canceling those spectator ions in both side (Ba^2+ and Br-), look like this:

H+(aq) + NO3-(aq) + Na+(aq) + OH-(aq) →Na+(aq) +NO3(aq) + H2O(l)

H+(aq) +  OH-(aq) → H2O(l)

7 0
4 years ago
If a substance has a mass of 12.50 g and takes up 3.4 mL of space, what is the density?
miskamm [114]

Answer:

The answer is

<h2>3.68 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass of substance = 12.50 g

volume = 3.4 mL

The density of the substance is

density =  \frac{12.50}{3.4}  \\  = 3.676470588...

We have the final answer as

<h3>3.68 g/mL</h3>

Hope this helps you

7 0
3 years ago
What is the effect of dilution on the pH of a buffer?
OLEGan [10]
I wish I knew I’m sorry
3 0
4 years ago
Read 2 more answers
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