3 years ago

I’m extremely stuck on this, please help

Chemistry

1 answer:

nataly862011 [7]3 years ago

5 0

Answer:

ice: 2,100 J/(kg·K)

water: 4,200 J/(kg·K)

water vapor: 2,000 J/(kg·K)

basalt: 840 J/(kg·K)

granite: 790 J/(kg·K)

aluminum: 890 J/(kg·K)

iron: 450 J/(kg·K)

copper: 380 J/(kg·K)

lead: 130 J/(kg·K)

Explanation:

Specific heat is the amount of thermal energy you need to supply to a sample weighing 1 kg to increase its temperature by 1 K.

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How much CaCO3 would have to be decomposed to produce 247 g of CaO

vovangra [49]

441 g CaCO₃ would have to be decomposed to produce 247 g of CaO

<h3>Further explanation</h3>

Reaction

Decomposition of CaCO₃

CaCO₃ ⇒ CaO + CO₂

mass CaO = 247 g

mol of CaO(MW=56 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{247}{56}\\\\mol=4.41$

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

$\tt \dfrac{1}{1}\times 4.41=4.41$

mass CaCO₃(MW=100 g/mol) :

$\tt mass=mol\times MW\\\\mass=4.41\times 100\\\\mass=441~g$

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