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2 years ago

Which one of the following is a common acid? A. Antacid

Chemistry

2 answers:

Black_prince [1.1K]2 years ago

8 0

Answer: i think its B

Explanation:

choli [55]2 years ago

4 0

<h2>Antacid is a common acid</h2>

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Which statement describes the energy changes that occur as bonds are brokes and a chemical reaction

Leni [432]

Answer:

Energy is released when bonds are broken, and energy is absorbed when bonds are formed.

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2 years ago

The brackets are indicating a(n) _____ bond. the brackets are indicating a(n) _____ bond. hydrogen polar covalent single (nonpol

Talja [164]

The brackets are indicating a(n) __Hydrogen___ bond.
1. Hydrogen

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3 years ago

A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f

viva [34]

Answer: -2.373 x 10^-24J/K(particles

Explanation: Entropy is defined as the degree of randomness of a system which is a function of the state of a system and depends on the number of the random microstates present.

The entropy change for a particle in a system depends on the initial and final states of a system and is given by Boltzmann equation as

S = k ln(W) .

where S =Entropy

K IS Boltzmann constant ==1.38 x 10 ^-23J/K

W is the number of microstates available to the system.

The change in entropy is given as

S2 -S1 = kln W2 - klnW1

dS = k ln (W2/W1)

where w1 and w2 are initial and final microstates

from the question, W2(final) = 0.842 x W1(initial), so:

= 1.38*10-23 ln (0.842)

=1.38*10-23 x -0.1719

= -2.373 x 10^-24J/K(particles)

4 0

3 years ago

The mass percent of carbon in a typical human is 18%, and the mass percent of 14C in natural carbon is 1.6 × 10-10%. Assuming a

Tema [17]

Answer:

4066 decay/s

Explanation:

Given that:-

The weight of the person is:- 190 lb

Also, 1 lb = 453.592 g

So, weight of the person = 86182.6 g

Also, given that carbon is 18% in the human body. So,

$\%\ Carbon=\frac{18}{100}\times 86182.6\ g=15512.868\ g$

Carbon-14 is $1.6\times 10^{-10}\ \%$ of the carbon in the body. So,

$\%\ Carbon-14=\frac{1.6\times 10^{-10}}{100}\times 15512.868\ g=2.48\times 10^{-8}\ g$

Also,

14 g of Carbon-14 contains $6.023\times 10^{23}$ atoms of carbon-14

So,

$2.48\times 10^{-8}\ g$ of Carbon-14 contains $\frac{6.023\times 10^{23}}{14}\times 2.48\times 10^{-8}$ atoms of carbon-14

Atoms of carbon-14 = $1.07\times 10^{15}$

Given that:

Half life = 5730 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac{ln\ 2}{5730}\ years^{-1}$

The rate constant, k = 0.00012 years⁻¹

Also, 1 year = $3.154\times 10^7$ s

So, The rate constant, k = $\frac{0.00012}{3.154\times 10^7}$ s⁻¹ = $3.8\times 10^{-12}\ s^{-1}$

Thus, decay events per second = $K\times atoms decayed$ = $3.8\times 10^{-12}\times 1.07\times 10^{15}\ decay/s$ = 4066 decay/s

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3 years ago

Write a balanced chemical equation for the combustion of hydrazine to produce nitrogen dioxide and water

loris [4]

Hairy funyon eeeeeeeeeeeeeeeeek

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2 years ago