Question

Two oranges and five lemons cost $2.75. Two oranges and nine lemons cost $4.15. PART A) Write a system of equations and solve it using the elimination technique. PART B) Using your solutions from part A, how much would five oranges and three lemons cost?

Answer 1

A) 2o+5l=2.75
-2o-9l = -4.15
———————-
-4l=-1.4
l= 0.35

2o+5(0.35)=2.75
2o+ 1.75= 2.75
2o=1
O= 1/2

B) 5(0.5) + 3(0.35) = 2.5+1.05= 3.55