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3 years ago

12

Write an expression, using an exponent, that is equivalent to 8\times8\times8\times8 .

1 answer:

weqwewe [10]3 years ago

3 0

Answer:

8^3

Step-by-step explanation:

8*8*8 is equivalent to 8^3 which equals a total of 512 units

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A catering service offers 4 appetizers, 9 main courses, and 7 desserts. A customer is to select 3 appetizers, 2 main courses, an

never [62]

Answer:

In 5040 ways.

Step-by-step explanation:

To solve this problem we will use combination without repetition which means:

C ( n k) = (n₁ k₁) (n₂ k₂) (n₃ k₃) = (4 3) (9 2) (7 3) =

(4 · 3 · 2 / 3 · 2 · 1) (9 · 8 / 2 · 1) (7 · 6 · 5 / 3 · 2 · 1) = 4 · 36 · 35 = 5040

It can be done in 5040 ways.

God with you!!!

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3 years ago

What is linear equation?<br> What is quadratic equation?

mr_godi [17]

in the linear equation the greatest power of the variables is 1 for example:2X+4 this is a linear equation as the greatest power of the variable X is 1 also by drawing it in a graph you will obtain a straight line
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4 years ago

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Please help answer the math question below

Ksju [112]

Answer:

C

Step-by-step explanation:

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3 years ago

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Jenny wants a total of 12 barbie dolls by the time she is 9 years old. Right now she has 4 barbie dolls. How many more does she

Gnoma [55]

She will need 8 more barbies, to reach a total of 12.

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3 years ago

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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, <em>W</em>, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

3 years ago