Well, their speeds are (

is Jack's speed, and

is Richard's.

They, together, can paint 12 houses in 35 days. To get a single house, we only have to calculate

which is very close to 3 (a bit below)
They are all prime numbers
No because In the relation , y is a function of x, because for each input x (1, 2, 3, or 0), there is only one output y. x is not a function of y,
Answer:
(4c-1)(y+3)
Step-by-step explanation:
4c(y+3) -(y+3)
=(4c-1)(y+3)
Step-by-step explanation:
Given:
and 
We can solve for f(x) by writing

Let 

Then


We know that f(0) = 0 so we can find the value for k:

Therefore,
