Answer:
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Step-by-step explanation:
Given that, the rate R(t) at which cars enter the highway is given the formula
The average rate of car enter the highway during first half hour of rush hour is the average value of R(t) from t=0 to t=30.
![=[100(t-0.0001\frac{t^3}{3})]_0^{30}](https://tex.z-dn.net/?f=%3D%5B100%28t-0.0001%5Cfrac%7Bt%5E3%7D%7B3%7D%29%5D_0%5E%7B30%7D)
![=100[(30-0.0001\frac{30^3}{3})-(0-0.0001\frac{0^3}{3})]](https://tex.z-dn.net/?f=%3D100%5B%2830-0.0001%5Cfrac%7B30%5E3%7D%7B3%7D%29-%280-0.0001%5Cfrac%7B0%5E3%7D%7B3%7D%29%5D)
=2901
The average rate of car is 
=97
On average, cars enter the highway during the first half hour of rush hour at a rate 97 per minute.
Answer:
Unit rate miles per day is, 3
Step-by-step explanation:
Unit rate are defined as the rate are expressed as quantity of 1 such that 2 miles per hour or 5 km per hour.
As per the given statement: A construction crew built 1/2 miles of road in 1/6 days
by unit rate definition;
After substituting the given values we have
⇒
or
Therefore, unit rate miles per day is, 3
Step-by-step explanation:
hhhthhg
Answer:
D. Part of the solution region includes a negative number of erasers purchased; therefore, not all solutions are viable for the given situation.
Step-by-step explanation:
I got it right on the practice
Answer:
9d^8
Step-by-step explanation:
i think
Answer:
100
Step-by-step explanation:
20%-10
20%*5=100%--10*5=100
