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2 years ago

Which of the following developmental milestones is likely achieved before a child's first birthday?

Advanced Placement (AP)

2 answers:

frozen [14]2 years ago

8 0

The correct answer is D. Reach for nearby objects

Explanation:

In human development, a developmental milestone refers to behavior or development that is expected at a certain age. In the case of the first year of life, this stage includes multiple developmental milestones, for example, at four months it is expected the infant responds to contact and rolls its body. In this context, one of the developmental milestones that can be expected before a child's first birthday is that she or he is able to reach nearby objects, because at that age children have more control over their bodies and therefore they can grab objects with more precision and even crawl or move their bodies towards the desired objects.

KIM [24]2 years ago

3 0

D. reach for nearby objects

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1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a NET DECREASE of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.

8 0

1 year ago

HELP APES FVLS !!

Brilliant_brown [7]

use of commercially produced fertilizers

Note: industrial revolution to agriculture

Hope this helps

4 0

3 years ago

international company headquarters, significant global financial functions, and a polarized social structure are defining charac

larisa86 [58]

Answer:

Globalization.

Explanation:

Globalization is the autonomy of all those parameters (economy, communication, etc.) that until recently sought to have borders within a protective state. The parameters that tend to break free and spread after globalization are trade, social structure, technology, culture, political system, knowledge, etc.

Thus, globalization is the word that describes the interdependence of the different national economies around the world, that is, the breaking of the borders of the different markets and the creation of a unified market at a global level, characterized by the deregulation of certain parameters such as labor or the interconnection of different populations through technology.

8 0

2 years ago

Read 2 more answers

A gumball machine contains 23 green gumballs, 52 red gumballs, 34 blue gumballs 61 yellow gumballs, and 30 pink gumballs. What p

Romashka-Z-Leto [24]

Total number of gumballs in the gumball machine =

23 + 52 + 34 + 61 + 30 = 200

% of the gumballs being red = 52/200 * 100

= 52/2

= 26 %

Hence, 26% of the gumballs are red in the gumball machine

4 0