Answer:
The age of the mother is 42 years, while the age of the girl is 7 years.
Step-by-step explanation:
Given that 1/6 of the age of a mother is the age of her daughter, to determine the age of the mother if the difference of their age is 35, the following calculations must be performed:
6 - 1/6 = 5/6
5/6 = 35
35/5 = 7
7 + 35 = 42 = 7 x 6
7 = 7 x 1
Therefore, the age of the mother is 42 years, while the age of the girl is 7 years.
Answer:
(f+g)(x)=4x+5
Step-by-step explanation:
Just add the two functions together:
(f+g)(x)=f(x)+g(x)=(10-2x)+(6x-5)=-2x+6x+10-5=4x+5
So (f+g)(x)=4x+5
Answer:
When raising a product to a power, raise each factor to the power, then multiply.
Step-by-step explanation:
(ab)^c = a^c * b^c
Aquarium tickets = $14.50 x 9 = $130.5
Wave pool tickets = $12.25 x 9 = $110.25
$130.50 -
$110.25 =
$20.25
The Wave pool will cost the least for 9 tickets.
It will cost $20.25 less than the Aquarium.
Answer:
A. The area in any normal distribution bounded by some score x is the same as the area bounded by the equivalent z-score in the standard normal distribution - false
B. A z-score is a conversion that standardizes any value from a normal distribution to a standard normal distribution - True
Step-by-step explanation:
A. The area in any normal distribution bounded by some score x is the same as the area bounded by the equivalent z-score in the standard normal distribution- This statement is false in the sense that it is a point that is equivalent to corresponding point of normal distribution.
B. A z-score is a conversion that standardizes any value from a normal distribution to a standard normal distribution. - This statement is true in the sense that z-score is in the normal standard distribution.
C. A z-score is an area under the normal curve - This statement is true in the sense that z-score is a conversion that standardizes any value from a normal distribution to a standard normal distribution.
D. If values are converted to standard z-scores, then procedures for working with all normal distributions are the same as those for the standard normal distribution - This statement is absolutely true
