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trapecia [35]
3 years ago
12

Which of the following is a point slope equation of a line that passed through the points (10,5) and (4-7)

Mathematics
1 answer:
levacccp [35]3 years ago
5 0

Answer:

<h2>y - 5 = 2(x - 10)</h2>

Step-by-step explanation:

The point-slope form of an equation of a line:

y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (10, 5) and (4, -7). Substitute:

m=\dfrac{-7-5}{4-10}=\dfrac{-12}{-6}=2

y-5=2(x-10)

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Step-by-step explanation:

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Using the quadratic formula then simplifying gives you :

±2√3

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Look at the circle you created that has point C (the midpoint of AB) as its center and passes through point A. What can you say
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The inscribed angle on the circumference of the circle subtended by the diameter at the center is a right angle

What can be said about segment AB is; Segment AB is the diameter of circle with midpoint at C

What can be said about angle BDA is; Angle BDA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BDA is 90°

What can be said about angle BEA is; Angle BEA is an inscribed angle of the circle with midpoint at C, subtended by the diameter AB at the center

The measure of angle BEA is 90°

The given diagram shows;

Circle with midpoint <em>C</em>, along AB, and radius AC

The diameter of circle C = AB

Circle with midpoint <em>A</em>, intersecting with circle <em>C</em> at points <em>D</em> and <em>E</em>

Tangents from point B on circle, <em>C</em>, intersect with circle <em>A</em> at points <em>D</em> and <em>E</em>

<em> </em>

Required parameters;

  • What can be said about AB

The segment AB is a line that intersects the circle <em>C</em> at two points and also passes through the the point <em>C</em> which is the center of the circle <em>C</em>

Therefore, the segment AB is the diameter of the circle with center at <em>C</em>

  • What can be said about angle BDA

The angle BDA is the inscribed angle of circle <em>C</em> subtended by the points <em>A</em> and <em>B</em> which specifies the diameter of the circle with midpoint <em>C</em>

Therefore, the angle BDA is subtended by the diameter of the circle at the center

According to circle theorem, we have;

Angle subtended at the center = 2 × The angle subtended at the circumference

The angle subtended at the center by the diameter AB = 180° (Angle on a straight line)

Therefore;

The angle subtended at the center = 180° = 2 × Angle BDA

Angle BDA = 180°/2 = 90°

Angle BDA  = 90°

  • What can be said about angle BEA

Similarly, we have;

The angle subtended at the center = 180° = 2 × Angle BEA

Angle BEA = 180°/2 = 90°

Angle BEA = 90°

Find out more about inscribed angles of a circle here:

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