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jekas [21]
3 years ago
11

Easy vector problem! show work/explain please :)

Mathematics
1 answer:
krek1111 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

a = 2i + 3j + zk

b = xi + 1j + 4k

Given a X b = 6i -14j +5k

a X  b  = | i   j   k|

              |2  3   z|

              |x   1    4|

a X b = i(12-z) - j(8 - xz) + k(2-3x) = 6i -14j +5k

equate the coefficients of i , j and k

12- z = 6;  implies z = 6

8 - xz = -14 implies 8 - 6x = -14

2-3x = 5     implies 2 - 3x = 5 implies  x = -1

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16. (-4) = what is the answer<br>​
kirill115 [55]

Answer

-64

just use ur calculator since my teacher let us use the calculator i just typed in 16.(-4) and got -64  

5 0
2 years ago
Read 2 more answers
9/17 15/34 6/17 9/34 geometric sequence?
zysi [14]
In a geometric sequence each number after the first is found by multiplying the previous number by a fixed number called the common ratio.

In an arithmetic sequence, each term is equal to the previous term plus or minus a constant called the common difference.

In your problem we have a sequence of numbers that appears to be decreasing in value, but on the surface it doesn't appear to be by any constant number... but if you look closely, the denominator 34 is exactly twice the other denominator 17. This would lead me to look at a common denominator to see if anything takes shape...

9/17 = 18/34
15/34
6/17 = 12/34
9/34

Now we see that each number is the previous number minus 3/34, so we have a common difference of 3/34.

This would match the definition of an arithmetic sequence and NOT a geometric sequence.
6 0
3 years ago
What city is this please no links
Artist 52 [7]

Answer:

fantasy if its wrong im sorry

7 0
3 years ago
Read 2 more answers
What is the square root of four
xz_007 [3.2K]

Answer:

It is +2 or since (+2)*(+2 ) gives. If you think that it would be (-2) also then you are wrong because root of a positive rational number is always positive number.

Step-by-step explanation:

Let the square root of four be ‘k’.

Then we have

(4)^1/2=k

(Squaring both sides)

4=(k)^2

=>(k)^2–4=0

=>(k)^2-(2)^2=0

=>[k+2][k-2]=0 {since (a)^2-(b)^2=(a+b)(a-b)}

if product of two numbers is 0 then either of one must be zero.

If k+2=0 then k=-2

If k-2=0 then k=2

From here we got two answers but -2 should be omitted because when we square an equation we add “root extra”which means that when we square an equation one root is added.

3 0
3 years ago
Find two numbers whose sum is 9 and whose difference is -1
faltersainse [42]

Answer:

4 and 5

Step-by-step explanation:

Make a system of equations:

x+y=9

x-y=-1

x=9-y

9-y-y=-1

9-2y=-1

-2y=-10

y=5

Since y=5, x must be 4 since 4+5=9 and 4-5=-1

Hope this helped!

4 0
3 years ago
Read 2 more answers
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